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Let be an entire function of finite order, and let be a rectifiable path on which . Let be the length of in the disc .
Find a path for which grows as slowly as possible, and estimate in terms of .
In particular, can such a path be found for which ?
Source: erdosproblems.com/1115
An accepted solution exists. The statement is false.
SOLVED, the site's label, with commentary recording a disproof by Gol'dberg and Eremenko. Their Theorems 1 and 2 give entire functions of order zero, growing barely above Hayman's logarithmic-square threshold, and of every finite order, such that no path on which has length inside the disc of radius ; the answer to the problem's question is therefore no, and the standing is solved, disproved (their claim page (Goldberg Eremenko, 1979)). The standing records a disproof where the label says only SOLVED, because the problem's definite question asks whether every entire function of finite order has a path with , and the accepted full claims refute that. Toppila's 1980 note proves the same theorem independently (Toppila's claim page (1980)), and Hayman's 1960 theorem, the yes-instances for functions with , is a partial claim (its claim page (Hayman, 1960)). The wider request for an optimal length estimate in terms of is not supplied by that counterexample, and no optimal replacement bound for every growth class is asserted here.