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Let . What is the maximum number of edges that a graph on vertices can contain if it does not have a -regular subgraph? Is it ?
Source: erdosproblems.com/182
An accepted solution exists. The statement is true.
Proved, the site's label. The answer to the yes-or-no part is
yes, first by Pyber's (Combinatorica 1985; an accepted
partial claim, refereed, on
its claim page (Pyber, 1985)).
Janzer and Sudakov's Theorem 1.2 (Forum Math. Pi 11 (2023), e19; refereed),
which the site credits with the resolution, gives for every a constant
with and, with the
Pyber--Rödl--Szemerédi construction, determines the order. The order is
known up to constants and not asymptotically: the construction of Pyber,
Rödl and Szemerédi (1995; Theorem 1, printed p. 42) gives
for every , and Chakraborti, Janzer,
Methuku and Montgomery (Trans. Amer. Math. Soc., online 18 August 2026;
cited from arXiv v2) prove that the maximum is
once is large in terms of , tight up to an absolute constant. No
asymptotic formula is known. The prize question of [Er78] for ,
whether , is settled in the negative by the lower bound. Two
accepted full claims, both refereed, carry the standing: Janzer and
Sudakov's, on
its claim page (Janzer
and Sudakov, 2022),
also reviewed through the curator's credit, and Chakraborti, Janzer,
Methuku and Montgomery's, on
its claim page (Chakraborti Janzer Methuku Montgomery, 2024).
Pyber's bound and the Pyber--Rödl--Szemerédi lower bound are accepted
partial claims, refereed, on
Pyber's page
and
the Pyber--Rödl--Szemerédi page.
One unreviewed proof claim of 2026-08-24 on the site's proof-claim tab
asserts the bound for induced -regular subgraphs, the
variant Szemerédi asked about, which implies the answer yes to the
yes-or-no part; it is a claimed partial claim on
its claim page (Korsky, 2026)
and bears no weight on the standing.