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Let with associated such that the congruence classes are disjoint (that is, every integer is for at most one ). How large can be in terms of ?
Source: erdosproblems.com/202
An accepted solution exists. Settled in another form, for example when its parts resolve differently or the question is open-ended.
SOLVED (LEAN). The answer is known at the sharp logarithmic scale. Put for , using natural logarithms. Then
Precisely, for every real there is such that every integer satisfies
This identifies the leading coefficient in the exponent. It does not assert or an exact formula at every finite . The ordinary proof is Ho's Theorem 1.1. The public formalization and verification evidence are described below, and the acceptance evidence is recorded on Ho's claim page (2026).