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Let be an infinite set and consider the following greedy algorithm for a rational : choose the minimal such that and repeat with replaced by . If this terminates after finitely many steps then this produces a representation of as the sum of distinct unit fractions with denominators from .
Does this process always terminate if has odd denominator and is the set of odd numbers? More generally, for which pairs and does this process terminate?
Source: erdosproblems.com/282
No claim settles this problem.
Open on the site: the label is OPEN (no last-edited date shown;), and the site marks the problem as not resolvable by a finite computation. The frontmatter standing open, claim none, rests on no claim page: the site's proof-claim tab is empty, and no manuscript located claims either question. No proof, disproof or accepted resolution of the odd-denominator question, and no classification of the terminating pairs , was found in the search whose scope the Current assessment records. The published sources cited state the odd-denominator question as open (Pihko 2001 and 2010, Louwsma and Martino 2023, Koizumi 2025); the results recorded are existence criteria, which say which rationals have a representation at all, and termination for prescribed finite numbers of steps, none of which decides termination in general. This is a bounded negative finding, not a certificate of openness.