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Suppose that we have a family of subsets of such that for all and for every we have . Then
Source: erdosproblems.com/83
An accepted solution exists. The statement is true.
The site labels the problem PROVED (LEAN), crediting Ahlswede and Khachatrian [AhKh97]; the Lean behind the qualifier is described below. The accepted claim is the 4m-conjecture from the complete intersection theorem.