For any integer n=∏pkp let Q2(n) be the powerful
part of n, so that
Q2(n)=pkp≥2∏pkp.
Is it true that, for every ϵ>0 and ℓ≥1, if n is sufficiently
large then
Q2(n(n+1)⋯(n+ℓ))<n2+ϵ?
If ℓ≥2 then is
n→∞limsupn2Q2(n(n+1)⋯(n+ℓ))
infinite?
If ℓ≥2 then is
n→∞limnℓ+1Q2(n(n+1)⋯(n+ℓ))=0?