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Source. The Diagonal Lemma 2.2 and Corollary 2.3 (p. 342), proved in §2.6 (pp. 342–343), with Remark 2.7 (p. 343), of G. Grekos, L. Haddad, C. Helou, J. Pihko, On the Erdős–Turán conjecture, Journal of Number Theory 102 (2003), no. 2, 339–352, the edition named on the source card.

Statement

Notation as on the Theorem 2.1 page: X[n]=X∩[0,n]X[n]=X\cap[0,n], B(x)\mathcal B(x) the bases of N[x]\mathbb N[x], B(N)\mathcal B(\mathbb N) the bases of N\mathbb N, s(P)=sup⁡nr(P,n)s(P)=\sup_n r(P,n) and ρ(x)\rho(x), Λ\Lambda the finite minima and the ET-lub.

Lemma 2.2 (the Diagonal Lemma) (p. 342). Let P=(Pi)i∈I\mathcal P=(P_i)_{i\in I} be a family of subsets of N\mathbb N indexed by an infinite set II. Then some A⊆NA\subseteq\mathbb N satisfies

(*) for every n∈Nn\in\mathbb N there are infinitely many i∈Ii\in I with A[n]=Pi[n]A[n]=P_i[n].

Such an AA is called a diagonal of P\mathcal P. Remark 2.7 (p. 343) notes that a diagonal can be chosen without the axiom of choice, taking at each stage the lexicographically first trace realized at infinitely many indices.

Corollary 2.3 (p. 342). Let P=(Pi)i∈I\mathcal P=(P_i)_{i\in I} be indexed by an infinite subset II of N\mathbb N, and let AA be a diagonal of P\mathcal P.

  1. If Pi∈B(i)P_i\in\mathcal B(i) for all i∈Ii\in I, then A∈B(N)A\in\mathcal B(\mathbb N).
  2. If s(Pi)≤ss(P_i)\le s for some s∈N∪{∞}s\in\mathbb N\cup\{\infty\} and all i∈Ii\in I, then s(A)≤ss(A)\le s.
  3. If Pi∈B(i)P_i\in\mathcal B(i) and ρ(Pi,i)=ρ(i)\rho(P_i,i)=\rho(i) for all i∈Ii\in I, then A∈B(N)A\in\mathcal B(\mathbb N) and s(A)=lim⁡x→∞ρ(x)=Λs(A)=\lim_{x\to\infty}\rho(x)=\Lambda.

Read depth. Claims checked: Lemma 2.2, Corollary 2.3 and Remark 2.7 were read clause by clause on the printed pp. 342–343. The proofs were read but not checked step by step.

Proof pointer

Lemma 2.2 is a nested pigeonhole construction (§2.6, pp. 342–343): since N[n]\mathbb N[n] has finitely many subsets, an infinite set of indices contains an infinite subset on which the trace Pi[n]P_i[n] is constant; doing this for n=0,1,2,…n=0,1,2,\ldots inside the previous index set gives increasing traces A(n)A(n), and AA is their union. For Corollary 2.3, r(A,n)r(A,n) depends only on A[n]A[n], so it equals r(Pi,n)r(P_i,n) for infinitely many ii, in particular for some i≥ni\ge n; this transfers coverage of nn and every uniform bound. Part 3 adds that r(Pi,n)≤ρ(i)≤lim⁡ρr(P_i,n)\le\rho(i)\le\lim\rho for i≥ni\ge n, and Lemma 1.3 gives the reverse inequality.

Bears on

  • Problem 28: this is the compactness step of the paper's Theorem 2.1, which reformulates the problem as the divergence of ρ(x)\rho(x); on its own it proves nothing about the problem.
  • Problem 1145: the lemma applies to any family of sets, so a two-set version would preserve local conditions such as coverage of an interval and a uniform bound on the cross counts; the problem's condition an/bn→1a_n/b_n\to1 is not a condition on any finite trace, and the paper gives nothing that carries it to the diagonal (an observation recorded here, not in the paper).