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Statement

Setting (p. 1). For A⊆ZA\subseteq\mathbb Z and n∈Zn\in\mathbb Z, RA(3)(n)R_A^{(3)}(n) counts the pairs (a1,a2)∈A×A(a_1,a_2)\in A\times A with a1+a2=na_1+a_2=n and a1≤a2a_1\le a_2. The paper prints the defining set of pairs and compares these functions as counts. N\mathbb N is the set of positive integers.

Theorem 2 (Chen and Wang [CW03], p. 2). Define T:N→{1,−1}T:\mathbb N\to\{1,-1\} by

T(1)=1,T(2n)=−T(2n−1),T(2n+1)=−T(n+1)(n∈N),T(1)=1,\qquad T(2n)=-T(2n-1),\qquad T(2n+1)=-T(n+1)\qquad(n\in\mathbb N),

and put A={n∈N:T(n)=1}A=\{n\in\mathbb N:T(n)=1\}, B={n∈N:T(n)=−1}B=\{n\in\mathbb N:T(n)=-1\}. Then RA(3)(n)=RB(3)(n)R_A^{(3)}(n)=R_B^{(3)}(n) for all integer n≥3n\ge3.

The only change from Dombi's Theorem 1 is the sign in the recursion at odd arguments, and the range is n≥3n\ge3 rather than all n∈Nn\in\mathbb N. The theorem is Chen and Wang's (Y.-G. Chen and B. Wang, On the additive properties of two special sequences, Acta Arith. 110 (2003), no. 3, 299--303); the paper gives it a new proof common with Theorem 1.

Footnote 1 (p. 2). Dombi had conjectured that no A,B⊆NA,B\subseteq\mathbb N with infinite symmetric difference satisfy RA(3)(n)=RB(3)(n)R_A^{(3)}(n)=R_B^{(3)}(n) for nn large enough; Theorem 2 shows that such sets exist.

Essential uniqueness (p. 3, unnumbered). For a partition N=A∪B\mathbb N=A\cup B with T(n)=1T(n)=1 on AA and T(n)=−1T(n)=-1 on BB, the paper says its proof shows that RA(3)(n)=RB(3)(n)R_A^{(3)}(n)=R_B^{(3)}(n) for all sufficiently large nn if and only if T(1)+⋯+T(2n)=0T(1)+\cdots+T(2n)=0 and T(2n)=T(n)T(2n)=T(n) for all but finitely many n∈Nn\in\mathbb N. It states, leaving the check to the reader, that this is equivalent to the existence of n0∈Nn_0\in\mathbb N with T(2n)=−T(2n−1)T(2n)=-T(2n-1) and T(2n−1)=−T(n)T(2n-1)=-T(n) for n≥n0n\ge n_0, and T(1)+⋯+T(2n0)=0T(1)+\cdots+T(2n_0)=0.

Source. Vsevolod F. Lev, Reconstructing integer sets from their representation functions, Electron. J. Combin. 11 (2004), no. 1, Research Paper 78, 6 pp., doi:10.37236/1831: the statement and footnote 1 on p. 2, the common proof of Theorems 1 and 2 and the uniqueness remark on p. 3 (Section 2, pp. 3--4). The edition read is identified on the source card.

Read depth. Claims checked: the definitions and the statement were read clause by clause on the printed pages. The proof was read but not checked step by step. Nothing here is independently reviewed.

Proof pointer

P. 3. The argument is that of Theorem 1 with j=3j=3: twice the generating series of RA(3)R_A^{(3)} is α(x)2+α(x2)\alpha(x)^2+\alpha(x^2), so the difference of the two series becomes a series in x2nx^{2n} with coefficients −T(2n)+T(n)-T(2n)+T(n). The recursion gives T(2n)=T(n)T(2n)=T(n) for every n≥2n\ge2; it fails only at n=1n=1, where T(2)=−1T(2)=-1 and T(1)=1T(1)=1, so the coefficient of x2x^2 is non-zero and n=2n=2 is excluded.

Dependencies

No other result of the paper.

Bears on

No Erdős problem in this corpus. The theorem answers, for R(3)R^{(3)}, a question the paper attributes to Sárközy.