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Statement

Setting (p. 159). For a sequence A:a1<a2<⋯A:a_1<a_2<\cdots of positive integers, f(A:n)=f(n)f(A:n)=f(n) is the number of representations of nn as a sum of one or more consecutive terms of AA, and its average is

F(A;x)=F(x)=1x∑n=1xf(n).(1)F(A;x)=F(x)=\frac1x\sum_{n=1}^{x}f(n).\qquad(1)

Equation (5) (p. 160). For AA the sequence of primes, ai=pia_i=p_i,

F(x)∼log⁡2.(5)F(x)\sim\log2.\qquad(5)

Consequence (p. 161). Since the average value of f(n)f(n) is log⁡2\log2, the paper concludes that f(n)=0f(n)=0 for infinitely many nn.

Context (pp. 159--160). For contrast the paper recalls LeVeque's results: for AA the positive integers, F(x)=12log⁡x+γ+12log⁡2−12+O(x−1/2)F(x)=\frac12\log x+\gamma+\frac12\log2-\frac12+O(x^{-1/2}) (equation (2), p. 159), and for AA an arithmetic progression of positive terms with common difference dd, F(x)=12log⁡x+γ−12log⁡d2−12+O(x−1/2)F(x)=\frac12\log x+\gamma-\frac12\log\frac d2-\frac12+O(x^{-1/2}) (equation (4), p. 160); both give F(x)∼12log⁡xF(x)\sim\frac12\log x (equation (3)). The paper states, without giving the argument, that a variation of its method shows (3) holds for every sequence of positive asymptotic density; the density does not enter the leading term.

Source. L. Moser, Notes on Number Theory III: On the sum of consecutive primes, Canad. Math. Bull. 6 (1963), no. 2, 159--161, DOI 10.4153/CMB-1963-013-1. Definitions (1)--(4) on pp. 159--160, equation (5) on p. 160, its proof on pp. 160--161 and the consequence on p. 161. The edition read is identified on the source card.

Read depth. Claims checked: the definitions, equation (5), the consequence and the stated context were read clause by clause on the printed pages; the proof was read for its structure. The paper writes out its final chain of asymptotic estimates but does not justify the steps, saying only that they can easily be justified using (8) and the prime number theorem.

Proof pointer

Pages 160--161. Each block of consecutive primes with sum at most xx contributes 11 to f(1)+⋯+f(x)f(1)+\cdots+f(x), and the number of such blocks of rr primes lies between π(x/r)−r\pi(x/r)-r and π(x/r)\pi(x/r) (inequality (6)), for rr up to the kk with p1+⋯+pk≤x<p1+⋯+pk+1p_1+\cdots+p_k\le x<p_1+\cdots+p_{k+1} (definition (7)). From pr≍rlog⁡rp_r\asymp r\log r the paper gets k≍x/log⁡xk\asymp\sqrt{x/\log x} (estimate (8)), so the error ∑r≤kr\sum_{r\le k}r is o(x)o(x). The prime number theorem then turns ∑r≤kπ(x/r)\sum_{r\le k}\pi(x/r) into an integral of x/(rlog⁡(x/r))x/(r\log(x/r)) over 1≤r≤k1\le r\le k, equal to x(log⁡log⁡x−log⁡log⁡(x/k))x(\log\log x-\log\log(x/k)), which is asymptotic to xlog⁡2x\log2 because x/kx/k is of the order of xlog⁡x\sqrt{x\log x}.

Dependencies

The prime number theorem and pr≍rlog⁡rp_r\asymp r\log r; no other result of the paper.

Bears on

  • Problem 358: the paper's f(A:n)f(A:n) is the problem's f(n)f(n) for a sequence of positive integers. Equation (5) and its consequence show that the primes are not an example for either question of the problem: f(n)=0f(n)=0 for infinitely many nn, so neither f(n)→∞f(n)\to\infty nor f(n)≥2f(n)\ge2 for all large nn holds for the primes. The paper does not mention Erdős or the problem and says nothing about other sequences beyond the averages recalled above.