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Statement

Lemma 1 (p. 447). Let CC be any sequence of positive integers, with counting function C(n)C(n). For l=1,2,…,Nl=1,2,\ldots,N let DlD_l be the number of elements cc of CC with (l−1)N<c≤lN(l-1)N<c\le lN. If

∑l=1NDl2≪N\sum_{l=1}^{N}D_l^2\ll N

(the paper's (5)), then

lim inf⁡n→∞C(n) (log⁡n)1/2n1/2<∞\liminf_{n\to\infty}\frac{C(n)\,(\log n)^{1/2}}{n^{1/2}}<\infty

(the paper's (6); the print writes the lower limit as an underlined lim⁡\lim).

The numbers DlD_l depend on NN. The print does not say for which NN the hypothesis (5) is assumed; the proof applies it at every large NN with one implied constant.

The paper introduces the lemma as the core of Erdős's argument for B2B_2-sequences (p. 447), and for its proof refers to Halberstam and Roth, Sequences (Oxford, 1966), pp. 89--90.

Source. John C. M. Nash, On B4B_4-sequences, Canad. Math. Bull. 32 (4) (1989), 446--449, doi:10.4153/CMB-1989-064-2; Lemma 1 and its proof on p. 447. The edition read is identified on the source card.

Read depth. Claims checked: the statement was read clause by clause on the printed page. The proof was read but not checked step by step. Nothing here is independently reviewed.

Proof pointer

Page 447. Let τ(N)\tau(N) be the infimum of C(n)(log⁡n/n)1/2C(n)(\log n/n)^{1/2} over n≥Nn\ge N, the quantity the proof bounds; the aim is τ(N)≪1\tau(N)\ll1 with an absolute implied constant. Cauchy's inequality gives (∑l≤N1/l)(∑l≤NDl2)≥(∑l≤NDl/l1/2)2\bigl(\sum_{l\le N}1/l\bigr)\bigl(\sum_{l\le N}D_l^2\bigr)\ge\bigl(\sum_{l\le N}D_l/l^{1/2}\bigr)^2. Partial summation writes ∑Dl/l1/2\sum D_l/l^{1/2} through the values C(lN)C(lN), and bounding each C(lN)C(lN) below by τ(N)(lN/log⁡lN)1/2\tau(N)(lN/\log lN)^{1/2} gives ∑Dl/l1/2≫τ(N)(N/log⁡N)1/2∑l≤N1/l\sum D_l/l^{1/2}\gg\tau(N)(N/\log N)^{1/2}\sum_{l\le N}1/l. Hence ∑Dl2≫Nτ(N)2\sum D_l^2\gg N\tau(N)^2, and (5) bounds τ(N)\tau(N). In the printed proof this quantity is written τA(N)\tau_A(N), with A(⋅)A(\cdot) in place of C(⋅)C(\cdot) and an integral sign where the infimum is meant (the proof uses only the lower bound it gives for each C(lN)C(lN)), and the last line cites (4) where (5) is the hypothesis used.

Dependencies

Cauchy's inequality and partial summation; no other result of the paper.

Bears on

  • Problem 41: the lemma is the step of the main theorem that turns a block count for 2A2A into the liminf bound (4) for (2A)(n)(2A)(n), from which the bound for the B4B_4-sequence AA follows; it concerns general sequences and says nothing about B3B_3-sequences, the case the problem asks about.