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Statement
Satz II (p. 668, quoted). "In jedem Intervall liegen mehr als Zahlen, welche als Summe von einer Primzahl und einer Potenz von darstellbar sind. Hier ist eine gegebene ganze Zahl und eine positive Konstante, welche nur von abhängt."
In the corpus's words: for a given integer there is a constant , depending only on , such that every interval contains more than integers of the form with prime.
The paper says only that is a given integer. Its proof needs : it counts the powers of up to as (11, p. 672), which requires . That count is the number of powers with ; whether is admitted does not matter, since the integers number at most up to . These remarks are observations of this page.
As with Satz I, "every interval " is to be read for sufficiently large: the proof (p. 673) gives for large , and footnote 1 (p. 668) defines positive density by for all sufficiently large . The theorem is a positive lower density statement; the paper does not show that the density exists.
Source. N. P. Romanoff, Über einige Sätze der additiven Zahlentheorie, Math. Ann. 109 (1934), 668--678, doi:10.1007/BF01449161; Satz II on p. 668, its proof on pp. 671--673, and the convergence of the auxiliary series on pp. 673--678. The edition read is identified on the source card.
Read depth. Claims checked: the statement and the proof were read clause by clause on the page images, including the convergence argument of pp. 673--678 and its Hilfssätze I and II (pp. 675--676); the cited estimates (Schnirelman's bound (5), the bounds (9) and (13)) were not re-derived. Nothing here is independently reviewed.
Proof pointer
Pp. 671--678. The inequality (1) of pp. 668--669 (see Satz I) is applied with the primes and the powers of . Since a difference with determines and , each is or (p. 672). With Schnirelman's bound (5) and the inequality for , the correlation sum is reduced (pp. 672--673) to
where is the multiplicative order of modulo . The paper proves (pp. 673--678) that the series
converges, which gives (12), , and then (1) with (7) and (11) gives (p. 673). The display (7) is reprinted on p. 672 with in both bounds; the computation on p. 673 uses the Chebyshev bounds of p. 670, which are what satisfies.
The convergence proof rewrites the series as times a sum over the primitive squarefree divisors of , bounds that by , the sum of over divisors of with (p. 674), and proves that converges. Writing with squarefree, the terms with are handled by (14, p. 675). For the terms with the paper proves two auxiliary results. Hilfssatz I (p. 675): if , the number of primes up to , is at least , then with absolute. Hilfssatz II (p. 676): the reciprocals of the first primes sum to less than for every , with absolute. These give (p. 678), where counts the factorizations of into factors greater than , and the second part of the series is then bounded by .
Dependencies
Inequality (1) of the same paper (pp. 668--669); Schnirelman's generalization of Brun's results, quoted as (5) (p. 670); Chebyshev's bounds for (7); the bound from the known estimates for Euler's function (13, p. 675); the bound on the number of prime factors used on p. 678.
Bears on
- Problem 244: for an integer the problem's integers are the integers , so Satz II with gives them positive lower density; it says nothing about non-integer . The problem's claim page for this paper records this partial result.
- Problem 851: with , Satz II says that the integers have positive lower density, the case of one prime divisor with a positive constant in place of the problem's ; it does not give the density bound the problem asks for.
- Problem 16: with , Satz II gives positive lower density to the integers , and so, since at most of them up to have , to the odd integers of that form (an observation of this page). The problem's claim page cites the theorem for this fact; the theorem does not decide the problem.
- Problem 205: the problem lists the paper as a reference. With , Satz II gives a positive lower density of integers with prime, so ; the problem asks about all sufficiently large integers, and the theorem does not bear on its answer.