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Source. Theorem 4.3 of Section 4, p. 137, with Lemma 4.1 (pp. 137--138), the proof (pp. 138--139) and Remark 4.1 (p. 139), of A. Sárközy and V. T. Sós, On additive representation functions, in R. L. Graham et al. (eds.), The Mathematics of Paul Erdős I, Springer, 1997, 129--150, doi:10.1007/978-3-642-60408-9_11, as identified on the source card.
Statement
Setting (pp. 130 and 137). For and , is the number of solutions of with and . For , is the set of with , and is its counting function. The counting function of a set is .
Theorem 4.3 (p. 137, quoted). "Let and let be positive integers. Then there is an infinite set such that writing"
"we have"
"and"
"where ."
The first estimate holds for each . The paper notes the case , : there is a set with for all but of the (p. 137). The theorem answers, in the negative, the authors' earlier expectation that the conclusion of their Problem 4.1 survives when is bounded only outside a thin set of (p. 137). Here .
Remark 4.1 (p. 139). For positive rationals with sum , the authors say the same idea gives an infinite with for some ; the print gives the range of as , read as , and refers to the theorem as Theorem 4. No proof is given. They expect the analogue with arbitrary densities to hold, with a harder proof.
Read depth. Claims checked: the setting, the statement, Lemma 4.1 and Remark 4.1 were read clause by clause on the printed pages, and the proof was read for its structure. Nothing here is independently reviewed.
Proof pointer
Pages 137--139. Lemma 4.1 (pp. 137--138) takes , the integers whose base- digits are all or , and , the integers whose base- digits are all or . Its four parts are: every is with , in exactly one way; the counting functions of and of are , since the sums in have no base- digit ; and, for , the with number (the print's display of this last part omits the restriction ). With the elements of and , the set is
A large then has exactly representations as a point of the -th block plus a point of , by the unique representation in Lemma 4.1 applied once for each , ; the sums of two block elements and of two elements of are in number by Lemma 4.1. The print's index in the first step (p. 138) is read as , which is how the step's display (4.21) writes it.
Dependencies
Lemma 4.1 (pp. 137--138) of the same paper, proved there in a few lines.
Bears on
- Problem 14: the case , gives an infinite for which all but integers in have exactly one representation with . The set contains ; translating it by (an observation of this page, not of the paper) gives a set of positive integers with the same bound, since it moves each count of representations from to . The exponent exceeds , so this neither contradicts the lower bound the problem asks about nor answers whether exceptions are possible.