Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Source. Proposition 5.2, p. 9, proved on pp. 9–10, of David Turturean, A Negative Answer to Erdős Problem #870, preprint dated April 2026 (11 pp.), https://www.overleaf.com/read/gknkvvxrymfv; the edition read is named on the source card.
Statement
Proposition 5.2 (p. 9). For every integer and every there is a set such that is an additive basis of order , for all sufficiently large , and contains no minimal additive basis of order .
Bases and are in the at-most- sense of Theorem 1.1.
Proof pointer
Pp. 9–10. With , take and from Proposition 2.3, with , and from Lemma 5.1, and put . An -tuple of fillers fixes the residue and at most two elements of the quotient, which gives the basis property and, summed over tuples, the logarithmic count. For an order- subbasis , the rigid residue forces to be an at-most-two basis; by Proposition 2.3 some can be dropped, and shows that the fillers in reach every residue, so is still an order- basis.
Dependencies
Proposition 2.3 and Lemma 5.1. Read depth: claims checked; the statement and proof were read clause by clause on the print.
Bears on
- Problem 870: the cases of Theorem 1.1, with the problem site's at-most- count of representations.