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Source. Proposition 5.2, p. 9, proved on pp. 9–10, of David Turturean, A Negative Answer to Erdős Problem #870, preprint dated April 2026 (11 pp.), https://www.overleaf.com/read/gknkvvxrymfv; the edition read is named on the source card.

Statement

Proposition 5.2 (p. 9). For every integer k≥4k\ge4 and every C>0C>0 there is a set E⊆NE\subseteq\mathbb N such that EE is an additive basis of order kk, RE,k(n)≥Clog⁡nR_{E,k}(n)\ge C\log n for all sufficiently large nn, and EE contains no minimal additive basis of order kk.

Bases and RE,kR_{E,k} are in the at-most-kk sense of Theorem 1.1.

Proof pointer

Pp. 9–10. With h=k−2h=k-2, take AA and η2\eta_2 from Proposition 2.3, LL with Lη2>CL\eta_2>C, and N,M,F,τN,M,F,\tau from Lemma 5.1, and put E=MA∪FE=MA\cup F. An hh-tuple of fillers fixes the residue and at most two elements of AA the quotient, which gives the basis property and, summed over LL tuples, the logarithmic count. For an order-kk subbasis TT, the rigid residue τ\tau forces D={a∈A:Ma∈T}D=\{a\in A:Ma\in T\} to be an at-most-two basis; by Proposition 2.3 some d∈Dd\in D can be dropped, and A(x)=o(x)A(x)=o(x) shows that the fillers in TT reach every residue, so T∖{Md}T\setminus\{Md\} is still an order-kk basis.

Dependencies

Proposition 2.3 and Lemma 5.1. Read depth: claims checked; the statement and proof were read clause by clause on the print.

Bears on

  • Problem 870: the cases k≥4k\ge4 of Theorem 1.1, with the problem site's at-most-kk count of representations.