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Statement
The properties are those of the paper's definitions.
Theorem 1 (p. 2, quoted). "$AP\Rightarrow QP\Rightarrow CP\Rightarrow C\Rightarrow DW$, and none of these implications is reversible."
The implications are among properties of sets of positive integers: each says that every set with the left-hand property has the right-hand one, and irreversibility means that for each implication some set has the right-hand property but not the left-hand one.
Source. Brown, T. C., Erdős, P. and Freedman, A. R., Quasi-progressions and descending waves, J. Combin. Theory Ser. A 53 (1990), no. 1, 81--95, doi:10.1016/0097-3165(90)90021-N, read in the authors' copy identified on the source card, whose pages are numbered 1 to 13: the statement on p. 2, the proof on pp. 2--4.
Read depth. Claims checked: the statement was read on the print's page. The proof was read but not checked step by step. Nothing here is independently reviewed.
Proof pointer
Section 2, pp. 2--4. The first two implications are immediate from the definitions. For , order the generators of an -cube decreasingly; the partial sums form an -term descending wave. For , an induction on shows that every sufficiently long contains an -cube: split a long combinatorial progression into blocks, find an -cube in each, and use the pigeonhole principle on the finitely many possible generator tuples to find two blocks whose cubes share generators, which together give an -cube.
The counterexamples: for , the partial sums of the powers of two rearranged into arbitrarily long decreasing blocks have property DW but no 2-cube, by uniqueness of binary expansions; for , the integers whose decimal digits are all 0 or 1; for and , sets built from Justin's infinite 0-1 sequence with no five adjacent blocks of equal composition.
Dependencies
The last two counterexamples use the existence of Justin's sequence, cited as J. Justin, Characterization of the repetitive commutative semigroups, J. Algebra 21 (1972), 87--90 (p. 4).
Bears on
- Problem 782: by , if the squares had property QP (the problem's first question answered yes) they would have property C (its second question answered yes); equivalently, a negative answer to the second question gives a negative answer to the first. This is an observation of this page; the theorem decides neither question.