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Source. Lemma 4.2, p. 29, with the definitions on pp. 28--29 of Section 4.2 (pp. 28--31), of Shmuel Onn, Convex Discrete Optimization, arXiv:math/0703575v1 [math.OC] (20 March 2007), published in the Encyclopedia of Optimization (2009), 513--550, as identified on the source card. Labels and pages are those of the arXiv preprint.

Setting

Section 4.2 (pp. 28--31), definitions on pp. 28--29. For u,v∈Znu,v\in\mathbb Z^n, uu is conformal to vv, written u⊑vu\sqsubseteq v, when ∣ui∣≤∣vi∣|u_i|\le|v_i| and uivi≥0u_iv_i\ge0 for i=1,…,ni=1,\ldots,n: the two vectors lie in a common closed orthant and each coordinate of uu is at most the matching coordinate of vv in absolute value. The paper notes that ⊑\sqsubseteq is a well partial order (Dickson's lemma), so every subset of Zn\mathbb Z^n has finitely many ⊑\sqsubseteq-minimal elements.

For an integer matrix AA with nn columns, $\mathcal L(A)={x\in\mathbb Z^n:Ax=0}$ is the lattice of its linear integer dependencies, and the Graver basis G(A)\mathcal G(A) is the set of ⊑\sqsubseteq-minimal elements of L(A)∖{0}\mathcal L(A)\setminus\{0\}. A finite sum u=∑iviu=\sum_iv_i is conformal when vi⊑uv_i\sqsubseteq u for every ii (p. 29).

The paper records, without proof, that G(A)\mathcal G(A) is centrally symmetric, that its elements are primitive (entries relatively prime), that every circuit of AA, a nonzero primitive element of L(A)\mathcal L(A) of minimal support, lies in G(A)\mathcal G(A), that G(A)\mathcal G(A) coincides with the set of circuits when AA is totally unimodular (with more in its §5.1), and that in general G(A)\mathcal G(A) is much larger (p. 29). Its example is A=(1,2,1)A=(1,2,1), with G(A)=±{(2,−1,0),(0,−1,2),(1,0,−1),(1,−1,1)}\mathcal G(A)=\pm\{(2,-1,0),(0,-1,2),(1,0,-1),(1,-1,1)\}, where the first three pairs are the circuits and (1,−1,1)(1,-1,1) is not (p. 29).

Statement

Lemma 4.2 (p. 29). Let AA be any integer matrix. Every h∈L(A)∖{0}h\in\mathcal L(A)\setminus\{0\} can be written as a conformal sum h=∑igih=\sum_ig_i of Graver basis elements gi∈G(A)g_i\in\mathcal G(A), not necessarily distinct.

Proof pointer

P. 29, by induction on the well partial order ⊑\sqsubseteq: a non-minimal hh has some h′∈G(A)h'\in\mathcal G(A) with h′⊏hh'\sqsubset h, and h−h′h-h' is a nonzero element of L(A)\mathcal L(A) strictly below hh, to which the induction applies. The paper uses the lemma for Lemma 4.3 (p. 30), the Graver basis as a set of improving directions, and for Lemma 5.3 (p. 42), that G(A)\mathcal G(A) covers all edge-directions of the integer hull conv{x∈Zn:Ax=b, l≤x≤u}\mathrm{conv}\{x\in\mathbb Z^n:Ax=b,\ l\le x\le u\}.

Dependencies

The definitions of Section 4.2 only. Read depth: claims checked; the definitions, the remarks on circuits and the lemma were read clause by clause on pp. 28--29, and the proof was checked.

Dissociation as a Graver condition

An observation of this page, not of the paper. Let B={b1,…,bk}B=\{b_1,\ldots,b_k\} be a finite set of distinct nonnegative integers and A=(b1,…,bk)A=(b_1,\ldots,b_k) the 1×k1\times k matrix. Two subsets X≠YX\ne Y of BB have equal sums exactly when ε=1X−1Y\varepsilon=1_X-1_Y is a nonzero element of L(A)\mathcal L(A) with entries in {0,±1}\{0,\pm1\}, and every such ε\varepsilon arises this way. Each conformal summand of such an ε\varepsilon again has entries in {0,±1}\{0,\pm1\} and support inside that of ε\varepsilon. So by Lemma 4.2, BB has distinct subset sums exactly when G(A)\mathcal G(A) has no element with all entries in {0,±1}\{0,\pm1\}. Circuits do not suffice for this test: for B={1,2,3}B=\{1,2,3\} the relation 1+2−3=01+2-3=0 gives the Graver element (1,1,−1)(1,1,-1), while the circuits ±(2,−1,0)\pm(2,-1,0), ±(3,0,−1)\pm(3,0,-1), ±(0,3,−2)\pm(0,3,-2) all have an entry outside {0,±1}\{0,\pm1\}.

Bears on

  • Problem 774: a language only. Through the observation above, the lemma rewrites dissociation of a finite set as the absence of Graver elements with entries in {0,±1}\{0,\pm1\}; it says nothing about which sets are proportionately dissociated or about unions of dissociated sets, and the paper does not consider the problem.