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Statement
For a sequence on the circle , the first terms cut the circle into intervals; an -span is the total length of consecutive intervals.
Theorem 2 (p. 2). Some sequence on , together with one universal constant with , has this property: for each there is a threshold, depending on , such that for every beyond it the intervals cut by satisfy
The paper proves it for two sequences, the golden-ratio Kronecker sequence with and the base-2 van der Corput sequence , and says the statement was conjectured in Brethouwer's 2024 Ph.D. thesis.
Source. F. Clément and S. Steinerberger, Balanced stick breaking, arXiv:2511.14637v1 (18 November 2025), Theorem 2 on p. 2 and Theorem 3 on p. 2 of that arXiv version, read in the text layer. The edition read is identified in the source digest.
Read depth. Claims checked: the statement was read clause by clause, with Theorem 3 and the remark that it implies Theorem 2; the proofs (Sections 2--3, pp. 3--11) were not read. Unrefereed; not independently reviewed.
Proof pointer
Theorem 3 (p. 2): for either sequence there is a universal such that for all , all sufficiently large depending on , and all ,
and the paper says the bound holds for all intervals of length on (p. 3). A short-interval discrepancy bound of this kind controls every -span from both sides, which gives Theorem 2 (the derivation is on p. 9). Section 2 (pp. 3--9) proves Theorem 3 for the van der Corput sequence through an ordering lemma (Lemma 1, p. 4) and Lemmas 2--4 (p. 5); Section 3 (pp. 9--11) proves it for the golden-ratio sequence through the three-distance structure of the Kronecker sequence (Lemma 5, p. 9). Not reconstructed here. The derivation of Theorem 2 from Theorem 3, with the quantifiers made explicit and the literal case of both statements recorded as false, is reconstructed (author-recorded, unreviewed) at its reconstruction page; the proofs of Theorem 3 remain unreconstructed.
Dependencies
Classical properties of the van der Corput and golden-ratio Kronecker sequences; the paper's own short-interval discrepancy estimates.
Bears on
- Problem 1221: with this gives for every (an authored one-line remark; at the printed statement would give , while ), so : the third expression of the de Bruijn--Erdős conjecture grows at most logarithmically if it grows at all. The 1949 lower bound is (5.7), .