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Source. Section 1° (formula (6), p. 513; the section runs pp. 512--513) of A. A. Gol'dberg, Sets on which the modulus of an entire function has a lower bound (Russian), Sibirsk. Mat. Zh. 20 (1979), no. 3, 512--518, 691, the edition named on the source card. The paper numbers its sections 1°, 2°, 3° and gives its results no theorem labels.

Statement

Setting (p. 512). For an entire function ff and c>0c>0, E(c)={z:∣f(z)∣>c}E(c)=\{z:|f(z)|>c\}, ∣E(c)∣|E(c)| is its planar (Lebesgue) measure, and M(r,f)=max⁡{∣f(z)∣:∣z∣=r}M(r,f)=\max\{|f(z)|:|z|=r\}. The problem the paper solves (Hayman's Problem 2.40) concerns entire functions that are not identically constant.

Result of 1° (formula (6), p. 513). Let ff be an entire function and let c>0c>0 be such that ∣E(c)∣<∞|E(c)|<\infty. Then

∫r0∞r drln⁡ln⁡M(r,f)<∞,\int_{r_0}^{\infty}\frac{r\,dr}{\ln\ln M(r,f)}<\infty ,

where the paper takes the lower limit r0>1r_0>1 (p. 512). This is the convergence half of Hayman's conjecture; that it cannot be sharpened is section 2°.

Read depth. Claims checked: the statement, the setting and the steps (1)--(6) were read on the page images of pp. 512--513. The inequality (1) that the proof imports from Pfluger and Arima was not checked against their papers, and nothing here is independently reviewed.

Proof pointer

Pages 512--513, outlined here. Write Γr\Gamma_r for the circle ∣z∣=r|z|=r, AA for the set of r>0r>0 at which Γr\Gamma_r is not contained in E(c)E(c), A(r)=A∩[1,r]A(r)=A\cap[1,r] for r>1r>1, and l(r)l(r) for the length of the longest arc of Γr∩E(c)\Gamma_r\cap E(c) when r∈Ar\in A. The proof starts from the Carleman-type estimate (1), proved independently by Pfluger and by Arima: ln⁡+ln⁡+M(er,f)≥π∫A(r)dt/l(t)−K\ln^+\ln^+M(er,f)\ge\pi\int_{A(r)}dt/l(t)-K for r>1r>1, with a constant KK. Finite area of E(c)E(c) gives that [1,∞)∖A[1,\infty)\setminus A has finite linear measure LL and that ∫Al(t) dt<∞\int_A l(t)\,dt<\infty (2). By (1) it suffices to show that rr divided by ∫A(r)dt/l(t)\int_{A(r)}dt/l(t) is integrable at infinity. On each dyadic block A∩[2j−1,2j)A\cap[2^{j-1},2^j), with 2N>2L2^N>2L and j≥N+1j\ge N+1, the Cauchy--Bunyakovsky inequality and the lower bound 2j−22^{j-2} for the block's measure bound the reciprocal of ∫dt/l(t)\int dt/l(t) over the block by 2−2j+42^{-2j+4} times ∫l(t) dt\int l(t)\,dt over the block (steps (3)--(5)); summing over the blocks and using (2) gives (6).

Dependencies

Inequality (1), cited from A. Pfluger, Compt. Rend. Acad. Sci. 229 (1949), 542--543, and K. Arima, J. Math. Soc. Japan 4 (1952), 62--66; the paper notes (p. 512) that Pfluger does not write (1) explicitly and that it follows easily from the stronger inequality he proves.

Bears on

  • Problem 1118: the problem's first question asks for the minimal growth of a non-constant entire ff for which E(c)E(c) has finite measure for some cc. This page gives the bound ∫∞r dr/ln⁡ln⁡M(r,f)<∞\int^\infty r\,dr/\ln\ln M(r,f)<\infty, which Hayman conjectured; section 2° shows it is best possible in the sense stated there. The paper states the question as Problem 2.40 of Hayman's list.