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Source. Theorem 14, p. 417, of R. J. Simpson, On a conjecture of Crittenden and Vanden Eynden concerning coverings by arithmetic progressions, Journal of the Australian Mathematical Society (Series A) 63 (1997), 396-420, as identified on the source card.
Statement
Notation as on the Theorem 1 page: is the progression of integers congruent to modulo .
The conjecture (p. 397, quoted). The paper states the conjecture that Crittenden and Vanden Eynden posed in 1972 as: "If is a collection of arithmetic progressions, each with modulus , such that , then ."
Minimal counterexample (p. 401). For an integer , a minimal counterexample for is a collection of arithmetic progressions, each of modulus at least , with and , such that (a) is the least integer for which such a collection exists, and (b) every other collection of progressions with these properties has sum of moduli at least the sum of the moduli of .
Notation of Theorem 13 (p. 416). is the number of primes less than , and over all primes less than . Both use strict inequality.
Theorem 14 (p. 417). If is a minimal counterexample for some , then is less than
Consequence stated by the paper (pp. 397, 416, 418). If the conjecture fails for some , then a minimal counterexample exists for that , and its is bounded as above; so for each fixed the conjecture can be settled by checking finitely many cases. The paper does not carry out this check. It reports that the check has been done for in the author's doctoral thesis (its reference [10]; pp. 397 and 419), and it notes that the number of cases grows exponentially with (p. 397).
The theorem is restricted to . The paper notes (p. 397) that the cases and of the conjecture coincide and are the theorem Crittenden and Vanden Eynden proved in 1970, and that the interval cannot be replaced by a shorter one: the collection of for and for covers but not .
Proof pointer
Pages 416-418. Assume misses . By Corollary 3 (§2), every modulus of a minimal counterexample is either a product of primes less than or a prime at least ; write and for the two parts, of sizes and , and let be the least modulus of a progression disjoint from . Theorem 1 gives , inequality (41), and Theorem 8 gives , inequality (42). Theorem 13 (p. 416) bounds and by functions of alone. Since must cover , reducing it via and applying the counting bound of Corollary 9 (p. 415) gives , inequality (45). With and (41) this yields , and part (c) of Theorem 13 turns this into the stated bound.
Dependencies
Theorem 1 (p. 397); Corollary 3 and Theorem 8 of §2; Corollary 9 (p. 415) of §3, which rests on the paper's Theorem 12 and its Lemmas 2 and 3; Theorem 13 (p. 416).
Read depth. Claims checked: the conjecture, the definition of a minimal counterexample, the notation of Theorem 13 and the statement of Theorem 14 were read clause by clause on pp. 397, 401, 416 and 417, and the discussion on pp. 418-419. The proof (pp. 416-418) was read for its structure only; §§2-3, on which it rests, were not checked.
Bears on
- Problem 275: background only. The problem is the conjecture's case (equivalently ), with the interval replaced by any consecutive integers, which the paper notes changes nothing (p. 397); Crittenden and Vanden Eynden proved that case. Theorem 14 concerns only and gives no proof or bound for the problem.