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Source. Theorem 3, p. 15, of Jean-Marie De Koninck, Florian Luca and Igor E. Shparlinski, Powerful numbers in short intervals, Bull. Austral. Math. Soc. 71 (2005), 11--16, doi:10.1017/S0004972700037953. See the source card.
Read depth. Claims checked: the statement was read clause by clause on the printed page. The proof (p. 15) was read for structure only. Nothing here is independently reviewed.
Statement
Theorem 3 (p. 15). For any positive integers and , the interval contains at most
squarefull numbers.
The implied constant is absolute. Since a number that is -full for some is squarefull, the same bound counts the integers in that are -full for at least one , which is how the introduction (p. 12) presents it. The statement is printed for all positive ; the bound is meaningful once .
Proof pointer
P. 15. With , the squarefull numbers in the interval are split by whether they have a prime factor with . Those that do are divisible by and number ; those that do not are counted by the Brun sieve, giving $\ll K\prod_{w\le p\le K}(1-1/p)\ll K\log\log K/\log K$.
Dependencies
The Brun sieve, cited as H. Halberstam and H.-E. Richert, Sieve methods (Academic Press, 1974), Theorem 2.2.
Bears on
- Problem 942: taking and gives at most powerful integers in for every . This upper bound is a power of , far above the bound the problem asks about, so it does not settle the problem. The paper does not mention the problem.