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Source. Theorem 3, p. 15, of Jean-Marie De Koninck, Florian Luca and Igor E. Shparlinski, Powerful numbers in short intervals, Bull. Austral. Math. Soc. 71 (2005), 11--16, doi:10.1017/S0004972700037953. See the source card.

Read depth. Claims checked: the statement was read clause by clause on the printed page. The proof (p. 15) was read for structure only. Nothing here is independently reviewed.

Statement

Theorem 3 (p. 15). For any positive integers LL and KK, the interval (L,L+K)(L,L+K) contains at most

O(Klog⁡log⁡Klog⁡K)O\left(\frac{K\log\log K}{\log K}\right)

squarefull numbers.

The implied constant is absolute. Since a number that is κ\kappa-full for some κ≥2\kappa\ge2 is squarefull, the same bound counts the integers in (L,L+K)(L,L+K) that are κ\kappa-full for at least one κ≥2\kappa\ge2, which is how the introduction (p. 12) presents it. The statement is printed for all positive KK; the bound is meaningful once log⁡log⁡K>0\log\log K>0.

Proof pointer

P. 15. With w=log⁡K/log⁡log⁡Kw=\log K/\log\log K, the squarefull numbers in the interval are split by whether they have a prime factor pp with w≤p≤Kw\le p\le K. Those that do are divisible by p2p^2 and number ≪K/log⁡K\ll K/\log K; those that do not are counted by the Brun sieve, giving $\ll K\prod_{w\le p\le K}(1-1/p)\ll K\log\log K/\log K$.

Dependencies

The Brun sieve, cited as H. Halberstam and H.-E. Richert, Sieve methods (Academic Press, 1974), Theorem 2.2.

Bears on

  • Problem 942: taking L=n2L=n^2 and K=2n+1K=2n+1 gives at most 1+O(nlog⁡log⁡n/log⁡n)1+O(n\log\log n/\log n) powerful integers in [n2,(n+1)2)[n^2,(n+1)^2) for every n≥1n\ge1. This upper bound is a power of nn, far above the bound (log⁡n)c+o(1)(\log n)^{c+o(1)} the problem asks about, so it does not settle the problem. The paper does not mention the problem.