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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Theorem (stated in the introduction, p. 168, unnumbered; proved in Section 1, pp. 168-170). There is a positive constant c3c_3 such that for infinitely many nn the number of solutions of

n=p2+q2,p, q prime,n=p^2+q^2,\qquad p,\ q\ \text{prime},

is greater than nc3/log⁡log⁡nn^{c_3/\log\log n}.

The introduction (p. 168) places this against Part I, J. London Math. Soc. 12 (1937), 133-136, where the same equation was shown to have more than nc2/(log⁡log⁡n)2n^{c_2/(\log\log n)^2} solutions for infinitely many nn by an elementary proof; the paper says the principal difference in Part II is that the argument requires Brun's method. The proof ends (p. 170) with a multiple n<2A4n<2A^4 of aia_i having more than n1/(50xlog⁡log⁡A)n^{1/(50x\log\log A)} solutions, where AA and the absolute constant xx are those of the proof pointer below. The paper does not say whether solutions are counted as ordered or unordered pairs; the two counts differ by at most a factor of 22, which does not affect the statement.

Read depth. Claims checked: the statement, the lemma and the final exponent were read clause by clause on the printed pages. The proof was read but not checked step by step. Nothing here is independently reviewed.

Proof pointer

Pages 168-170. With A=5⋅13⋯pkA=5\cdot13\cdots p_k the product of the first kk primes of the form 4d+14d+1, kk large, the paper writes A=a1a2⋯axA=a_1a_2\cdots a_x with xx a sufficiently large absolute constant and each aia_i having at least [k/x][k/x] prime factors.

Lemma (p. 168). Some aia_i has the property that in each of at least 78ϕ(ai)\tfrac78\phi(a_i) residue classes modulo aia_i the number of primes p<A2p<A^2 exceeds A2/(ϕ(ai)(log⁡A)2)A^2/(\phi(a_i)(\log A)^2).

The lemma is proved by contradiction (pp. 168-169): if it failed for every aia_i, the Brun-Titchmarsh upper bound for primes in arithmetic progressions (cited to E. C. Titchmarsh, Rend. di Palermo 54 (1930), 414-429) would leave fewer than A2/(4log⁡A)A^2/(4\log A) primes up to A2A^2 once xx is large, against the prime number theorem. For an aia_i given by the lemma, the count from Part I of solutions of z2+z′2≡0(modai)z^2+z'^2\equiv0\pmod{a_i} among those residue classes, more than 2V(ai)ϕ(ai)/162^{V(a_i)}\phi(a_i)/16 with V(ai)V(a_i) the number of prime factors of aia_i, together with k>log⁡A/(4log⁡log⁡A)k>\log A/(4\log\log A), gives many prime pairs p,q≤A2p,q\le A^2 with ai∣p2+q2a_i\mid p^2+q^2 (p. 169). All such sums are below 2A42A^4, so one multiple n<2A4n<2A^4 of aia_i carries more than n1/(50xlog⁡log⁡A)n^{1/(50x\log\log A)} of them (p. 170).

Dependencies

Part I, P. Erdős, On the sum and difference of squares of primes, J. London Math. Soc. 12 (1937), 133-136, for the congruence count and the shape of the argument; the Brun-Titchmarsh theorem; the prime number theorem, with that for arithmetic progressions (or an elementary substitute) for the bound on kk.

Bears on

  • Problem 979: the problem asks whether lim sup⁡nfk(n)=∞\limsup_n f_k(n)=\infty for every k≥2k\ge2, where fk(n)f_k(n) counts the representations of nn as a sum of kk kkth powers of primes. This theorem gives, for k=2k=2, more than nc3/log⁡log⁡nn^{c_3/\log\log n} representations for infinitely many nn, so f2f_2 is unbounded; Part I had already shown that. It says nothing about k≥3k\ge3.