Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
Setting (p. 53). For a planar point set write for its number of points, and let be the least integer such that every with contains points forming a convex -gon (the Esther Klein--Szekeres statement, proved by the authors in 1935, the paper's reference [2]). Section 2 stipulates (p. 54) that every set it considers has no three points collinear.
The construction (Section 2, pp. 54--57; announced on p. 53). For each there is a set of points in the plane that contains no convex -gon. The paper states no range for ; the blocks of the construction are indexed by , so it is meaningful from . Together with the 1935 upper bound this gives (p. 53)
The ingredient on cups and caps (p. 55). A sequence of points , , with is convex of length when the slopes of consecutive segments strictly increase, and concave of length when they strictly decrease; a sequence of length thus has points. The paper recalls from [2] that every set of more than points contains a concave sequence of length or a convex sequence of length , and gives an explicit set of exactly points containing neither, its longest concave sequence having length and its longest convex sequence length . The 1935 paper had stated the existence of such a set without proof.
The conjecture (p. 53). The authors conjecture that for every and say they can neither prove nor disprove it. Footnote 1 records that the conjecture is trivial for , was proved by Miss Klein for , and by E. Makai and P. Turán for .
Proof pointer
Pp. 55--57. is built recursively as the graph of an increasing integer-valued function on : its first points are a copy of and its last points a raised copy of , the shift chosen so that the upper block lies above every line through two points of the lower one and the lower block below every line through two points of the upper one. A concave sequence with two points in the lower block then has no point in the upper one, and a convex sequence with two points in the upper block has no point in the lower one, which gives the length bounds by induction.
As printed, the shift is too small in the smallest cases: , so is two points on a horizontal line and is three collinear points, against the paper's statements that every slope in is positive and that the upper block lies entirely above the lines through the lower one; the set of the next paragraph then has three collinear points for . Adding to each gives the strict separation the argument uses; the paper does not make this correction.
For , the paper places blocks : is a single point and each later block is a translate of a set , the translations (through constants , p. 56) moving each block down and to the right so that every segment joining two different blocks has negative slope, these slopes being ordered by the blocks' indices. The block sizes sum to . Inside a block every slope is positive, so a convex polygon in meets the first block it uses in a concave sequence, the last block in a convex sequence and every block between in a single point; the length bounds for then cap its number of vertices at (p. 57).
Dependencies
The bound and the cup--cap theorem are from P. Erdős and G. Szekeres, A combinatorial problem in geometry, Compositio Math. 2 (1935), 463--470 (the paper's reference [2]); the construction itself uses nothing beyond the definitions above.
Read depth. Claims checked: the statement on p. 53, its footnote, the definitions and the construction of Section 2 (pp. 54--57) were read clause by clause on the page images of the print; the slope inequalities on p. 56 were followed for structure, not recomputed; the recursion for was computed for . Nothing here is independently reviewed.
Source. P. Erdős and G. Szekeres, On some extremum problems in elementary geometry, Ann. Univ. Sci. Budapest. Eötvös Sect. Math. 3--4 (1960/1961), 53--62; the edition read is named on the source card.
Bears on
- Problem 107: the problem's (every points, no three on a line, contain a convex -gon) is for sets with no three points collinear, so the construction, with its shift corrected as above, gives , the lower half of the conjectured equality ; the paper's conjecture is that equality. The paper proves nothing toward the upper half.