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Source. M. Grinsztajn, A 63-dimensional counterexample to Borsuk's conjecture, unpublished note, May 2026, as described on the source card. Section 5 runs from p. 4 to p. 5: Lemma 4 and its proof are on p. 4, and the definitions of pp and XX are on p. 5.

Statement

Notation as in Lemma 3. Lemma 4 (p. 4): for a choice of b∈B1b\in B_1, the vector zb=xb−132S1z_b=x_b-\frac1{32}S_1 lies in WW, satisfies ∥zb∥2=78\lVert z_b\rVert^2=78, and for every c∈Cc\in C has zb⋅xc=18z_b\cdot x_c=18 if b∼cb\sim c and −6-6 if b≁cb\not\sim c.

The added point (p. 5). The note sets

t=222−113,p=tzb,t=\frac{\sqrt{222}-1}{13},\qquad p=tz_b,

so that tt is the positive root of 78t2+12t=10278t^2+12t=102, and defines X={xc:c∈C}∪{p}X=\{x_c:c\in C\}\cup\{p\}. It shows that pp is none of the xcx_c (those have squared norm 90, while ∥p∥2=78t2≠90\lVert p\rVert^2=78t^2\ne90), so X⊂R63X\subset\mathbb R^{63} and ∣X∣=321\lvert X\rvert=321.

Proof pointer

p. 4: xb⋅S1=384=132S1⋅S1x_b\cdot S_1=384=\frac1{32}S_1\cdot S_1 and, for i=2,3i=2,3, xb⋅Si=−192=132S1⋅Six_b\cdot S_i=-192=\frac1{32}S_1\cdot S_i, so zbz_b is orthogonal to S1,S2,S3S_1,S_2,S_3; the norm follows from the same values, and S1⋅xc=0S_1\cdot x_c=0 (Lemma 3) gives zb⋅xc=xb⋅xcz_b\cdot x_c=x_b\cdot x_c, which Lemma 2 evaluates.

Dependencies and read depth

Depends on Lemma 1, item 4, Lemma 2 and Lemma 3. Read depth: claims checked; Lemma 4, its proof and the definitions of tt, pp and XX were read on pp. 4--5.

Bears on. E0505: the 321st point of the set that the note's claim (Theorem 1) concerns.