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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

The pigeonhole principle (Section 1, p. 4). The paper credits to Pritikin the argument that a partial kk-tiling with ratio ρk\rho_k (the area of the plane over the area of the voids) can be translated so that all vertices of any given unit-distance graph with few enough vertices land on tiles, which then kk-color the graph; only translations are used. In the paper's terms, ⌈ρk−1⌉\lceil\rho_k-1\rceil, "the greatest integer strictly less than ρk\rho_k", is a number NN such that every unit-distance graph with NN vertices can be colored in kk colors, and ⌈ρk⌉\lceil\rho_k\rceil is a lower bound on the order of a (k+1)(k+1)-chromatic unit-distance graph (p. 4).

Consequence (abstract, p. 1, quoted). "It is thus shown that any unit-distance graph of order at most 6992 and 24 in the plane can be properly 6-colored and 5-colored, respectively." These follow from ρ6≈6992.1655504123\rho_6\approx6992.1655504123 (Section 2.3) and ρ5≈24.9627819109\rho_5\approx24.9627819109 (Section 2.2).

Table 2 (p. 14), "Bounds on the order of unit-distance graphs in the plane". The first two rows come from the tilings by the pigeonhole argument, for k≤4k\le4 from Croft's tilings (Section 2.1, p. 5); the last row records the smallest known kk-chromatic unit-distance graphs. A blank entry is blank in the print.

number of colors, kk1234567
kk-colorable graph by pigeonhole11312246992∞\infty
kk-chromatic graph by pigeonhole22413256993
smallest known kk-chromatic graph1237509

So, by the table, every unit-distance graph in the plane with at most 6992 vertices is 6-colorable, and a 7-chromatic one, if one exists, has at least 6993 vertices; every one with at most 24 vertices is 5-colorable, and a 6-chromatic one has at least 25 vertices. The paper gives no source for the entry 509; it matches the order of the 5-chromatic unit-distance graph of Parts' earlier paper (card), which this paper cites on p. 14 in another connection. The paper adds (p. 14) that the pigeonhole bounds are weak, far from the exact values for k≤4k\le4, and lists reasons, among them that rotations and the vertex degrees are not used.

Source. Jaan Parts, What percent of the plane can be properly 5- and 6-colored?, Geombinatorics 30 (2020), no. 1, 25-39; arXiv:2010.12668. Abstract (p. 1), the pigeonhole paragraph of Section 1 (p. 4) and Table 2 (p. 14). Pages are those of the arXiv version identified on the source card.

Read depth. Claims checked: the abstract's statement, the pigeonhole paragraph and every entry of Table 2 were read against the print. The paper describes the pigeonhole argument and cites Pritikin for it without proving it here, and the bounds rest on the numerically computed values of ρ5\rho_5 and ρ6\rho_6, which were not recomputed; nothing here is independently reviewed.

Proof pointer

The paper sketches the argument on p. 4: divide the tiling into many sufficiently small rectangles and count the translations that put at least one vertex of a given NN-vertex graph on a void; when N<ρkN<\rho_k some translation puts every vertex on a tile. The full argument is Pritikin's (D. Pritikin, All unit-distance graphs of order 6197 are 6-colorable, J. Combin. Theory Ser. B 73 (1998), 159-163).

Dependencies

The 6-tiling of Section 2.3 for the k=6k=6 entries and the 5-tiling of Section 2.2 for the k=5k=5 entries; Pritikin's pigeonhole argument.

Bears on

  • Problem 508: a finite unit-distance graph in the plane that is not 6-colorable, if one exists, has at least 6993 vertices, and one that is not 5-colorable has at least 25. The table bounds the order of such graphs only and does not bound the chromatic number of the plane.