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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Setting (pp. 1--3). For a set SS of nn points in Rd\mathbb{R}^d and any r ⁣:S→(0,∞)r\colon S\to(0,\infty), er(S)e_r(S) is the number of ordered pairs (x,y)(x,y) with x,y∈Sx,y\in S and ∣xy∣=r(x)|xy|=r(x), the edges of the favourite distance digraph determined by rr; fd(n)f_d(n) is the maximum of er(S)e_r(S) over all nn-point S⊂RdS\subset\mathbb{R}^d and all such rr. ud(n)u_d(n) is the maximum number of unordered pairs at distance 11 in an nn-point subset of Rd\mathbb{R}^d.

Theorem 2 (p. 3, attributed to Erdős and to Erdős and Pach, not proved in the paper). There are constants c1,c2>0c_1,c_2>0 such that for each d≥4d\ge4 and all n∈Nn\in\mathbb{N}, $u_d(n)\le\frac12\bigl(1-\frac1{\lfloor d/2\rfloor}\bigr)n^2+c_1n$ when dd is even and ≤12(1−1⌊d/2⌋)n2+c2(n/d)4/3\le\frac12\bigl(1-\frac1{\lfloor d/2\rfloor}\bigr)n^2+c_2(n/d)^{4/3} when dd is odd. The paper records that these bounds are tight up to the values of c1c_1 and c2c_2.

Theorem A (p. 3). With the constants c1,c2>0c_1,c_2>0 of Theorem 2, for each d≥4d\ge4 and all n∈Nn\in\mathbb{N},

fd(n)≤(1−1⌊d/2⌋)n2+{2c1nif d is even,2c2(n/d)4/3if d is odd.f_d(n)\le\Bigl(1-\frac{1}{\lfloor d/2\rfloor}\Bigr)n^2+ \begin{cases}2c_1n&\text{if $d$ is even,}\\ 2c_2(n/d)^{4/3}&\text{if $d$ is odd.}\end{cases}

Since fd(n)≥2ud(n)f_d(n)\ge2u_d(n) (p. 3: a set with r≡1r\equiv1 counts each unit pair twice), the paper notes that these bounds are also tight up to the values of the constants, and the abstract (p. 1) states the resulting asymptotics, fd(n)=(1−1⌊d/2⌋)n2+Θ(n)f_d(n)=\bigl(1-\frac1{\lfloor d/2\rfloor}\bigr)n^2+\Theta(n) for even dd and +Θ((n/d)4/3)+\Theta((n/d)^{4/3}) for odd dd, with absolute implied constants. This sharpens Theorem 1 (p. 2, credited to Avis, Erdős and Pach and to Erdős and Pach), fd(n)=(1−1⌊d/2⌋+o(1))n2f_d(n)=\bigl(1-\frac1{\lfloor d/2\rfloor}+o(1)\bigr)n^2 for any d≥4d\ge4.

Proof pointer

Pp. 3--4. Split the digraph into single edges (one direction only) and double edges (both directions), and take the connected components S1,…,SkS_1,\ldots,S_k of the double-edge graph, of sizes nin_i. Inside a component every edge is a double edge, so after scaling it is a unit distance graph and contributes at most 2ud(ni)2u_d(n_i) (the print writes ud(ni)u_d(n_i) in the first of its two facts on p. 4, but the calculation uses 2ud(ni)2u_d(n_i)); between two components only single edges occur, at most ninjn_in_j of them. Theorem 2 bounds each 2ud(ni)−12ni22u_d(n_i)-\frac12n_i^2, and the inequality ∑niα≤(∑ni)α\sum n_i^\alpha\le(\sum n_i)^\alpha for α≥1\alpha\ge1 collects the terms. The paper writes out the odd case and says the even case is similar.

Read depth

Claims checked: Theorems 1, 2 and A and the definitions were read clause by clause on the page images of pp. 1--4 of the arXiv preprint, and the proof on pp. 3--4 was followed. Theorem 2 is cited, not proved, in the paper and was not read at its source. Nothing here is independently reviewed.

Dependencies

None in the corpus. External input named by the paper: Theorem 2, the upper bounds for ud(n)u_d(n) of Erdős (Canad. J. Math. 1967) and Erdős and Pach (Combinatorica 1990).

Source. K. J. Swanepoel, Favorite distances in high dimensions, in Thirty Essays on Geometric Graph Theory (J. Pach, ed.), Algorithms and Combinatorics 29, Springer, New York, 2013, 499--519; read in the arXiv preprint arXiv:1108.4817 (24 August 2011), whose labels and pages are used here; see the source card.

Bears on

  • Problem 754: for d=4d=4, Theorem A reads f4(n)≤12n2+2c1nf_4(n)\le\frac12n^2+2c_1n. If every point xx of an nn-point set in R4\mathbb{R}^4 has at least f(n)f(n) points at one distance r(x)r(x), then n f(n)≤er(S)≤12n2+2c1nn\,f(n)\le e_r(S)\le\frac12n^2+2c_1n, so f(n)≤n2+2c1f(n)\le\frac n2+2c_1, the bound the problem asks for. The paper does not mention the problem; the site credits the problem to this bound.