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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Printed p. 62 = PDF p. 10, Section 5, "The order of magnitude of f(3)(n;k,k−2)f^{(3)}(n;k,k-2)", read on the page image; the result is unnumbered. With f(3)(n;k,s)f^{(3)}(n;k,s) as defined on p. 55 (recorded on theorem_section_4), the authors show that every 33-graph on nn vertices with at least

13(n[k−2k−1 (n−1)]+1)\tfrac13\Bigl(n\Bigl[\tfrac{k-2}{k-1}\,(n-1)\Bigr]+1\Bigr)

triples contains some kk vertices spanning at least k−2k-2 triples, so that f(3)(n;k,k−2)=O(n2)f^{(3)}(n;k,k-2)=O(n^2); in their words, "(constant) x n2n^2 triples suffice to ensure the existence of a G(3)(k,k−2)G^{(3)}(k,k-2)." Together with the bound f(3)(n;k,k−2)>cn2f^{(3)}(n;k,k-2)>cn^2, which the section opens by citing from the Theorem of Section 4, this fixes the order of magnitude as n2n^2.

Range of kk. The section states no range. The quoted lower bound needs k>3k>3 (the theorem's k>rk>r with r=3r=3, and then s=k−2>1s=k-2>1), and the upper bound's argument uses the Section 2 value of f(2)(n;k,s)f^{(2)}(n;k,s) in its range k/2<s<kk/2<s<k with k−1k-1 vertices and s=k−2s=k-2, which also needs k>3k>3; so the section's statements are for k≥4k\ge4 (a reading made here).

Source. W. G. Brown, P. Erdős and V. T. Sós, Some extremal problems on rr-graphs, in New Directions in the Theory of Graphs (Proc. Third Ann Arbor Conf., Univ. Michigan, 1971), Academic Press, New York (1973), 53--63, p. 62; the edition is identified in the source digest.

Proof sketch

Written here; the paper's argument is a few lines on p. 62. The degrees of the 33-graph sum to three times its number of triples, which exceeds n[k−2k−1(n−1)]n[\frac{k-2}{k-1}(n-1)], so some vertex xx lies in at least [k−2k−1(n−1)]+1[\frac{k-2}{k-1}(n-1)]+1 triples. The pairs completing xx to a triple form a graph on the other n−1n-1 vertices with that many edges. By the Section 2 value (p. 56) with k−1k-1 vertices and k−2k-2 edges, f(2)(n−1;k−1,k−2)=1+[(n−1)(k−3)/(k−2)]f^{(2)}(n-1;k-1,k-2)=1+[(n-1)(k-3)/(k-2)], and since (k−3)/(k−2)≤(k−2)/(k−1)(k-3)/(k-2)\le(k-2)/(k-1) this graph has k−1k-1 vertices spanning at least k−2k-2 edges. Adding xx gives kk vertices spanning at least k−2k-2 triples. The paper invokes the Section 2 result without writing out its value at these parameters; the comparison of the two fractions is a check made here, and the step was checked on 2026-10-08.

Dependencies

The value of f(2)(n;k,s)f^{(2)}(n;k,s) for k/2<s<kk/2<s<k quoted in Section 2 (p. 56), which the paper quotes as known, referring for Section 2 to its [5], and does not prove.

Bears on

  • Problem 1076: under the site's wording ex3(n,Fk)=f(3)(n;k,k−2)−1\mathrm{ex}_3(n,\mathcal F_k)=f^{(3)}(n;k,k-2)-1, and this bound with the Theorem of Section 4 shows that it has order n2n^2 for every k≥4k\ge4; it gives no constant, and so does not decide whether the asymptotic n2/6n^2/6 the problem asks about holds.
  • Problem 1157: the case r=3r=3, k=s+2k=s+2 with s≥2s\ge2 of the problem's function, where it settles the order of magnitude, Θ(n2)\Theta(n^2), but not the constant.