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Statement

Displays (2) and (3), printed p. 124. By a theorem of Rankin, which the paper cites, there is a constant c2>0c_2>0 such that for every kk some consecutive primes pr<pr+1p_r<p_{r+1} satisfy

k<pr<pr+1<2k,pr+1−pr>c2log⁡k⋅log⁡log⁡k⋅log⁡log⁡log⁡log⁡k(log⁡log⁡log⁡k)2.(2)k<p_r<p_{r+1}<2k,\qquad p_{r+1}-p_r>c_2\frac{\log k\cdot\log\log k\cdot\log\log\log\log k}{(\log\log\log k)^2}. \tag{2}

Every prime factor of the integers strictly between prp_r and pr+1p_{r+1} is less than kk, so that, for a constant c3>0c_3>0,

f(k)>c3log⁡k⋅log⁡log⁡k⋅log⁡log⁡log⁡log⁡k(log⁡log⁡log⁡k)2.(3)f(k)>c_3\frac{\log k\cdot\log\log k\cdot\log\log\log\log k}{(\log\log\log k)^2}. \tag{3}

On printed p. 125 Erdős calls the gap between (1) and (3) extremely large, suggests that f(k)f(k) is probably not much larger than the largest gap pr+1−prp_{r+1}-p_r between consecutive primes of (k,2k)(k,2k), and, citing a conjecture of Cramér, writes that "one might guess f(k)=(1+o(1))(log⁡k)2f(k)=(1+o(1))(\log k)^2" (4), adding: "The proof or disproof of (4) seems hopeless, there is of course no real evidence that (4) is true." The page also records that f(k)f(k) can be determined in finitely many steps by a theorem of Pólya and Störmer, without an effective bound; that Erdős cannot prove ff nondecreasing; and the values "f(2)=2f(2)=2, f(3)=f(4)=3f(3)=f(4)=3, f(5)=f(6)=4f(5)=f(6)=4. It seems likely that f(7)=f(8)=f(9)=f(10)=4f(7)=f(8)=f(9)=f(10)=4, but f(13)≥6f(13)\ge6."

Source. P. Erdős, On consecutive integers, Nieuw Arch. Wisk. (3) 3 (1955), 124--128; displays (2)--(3) on printed p. 124 (PDF p. 1) and (4) with the small values on p. 125 (PDF p. 2), read on the page images.

Read depth. Claims checked: the displays and the surrounding sentences were read clause by clause on the page images. The one-line deduction of (3) from (2) is as printed (a composite between consecutive primes of (k,2k)(k,2k) has all its prime factors below kk); Rankin's theorem is cited, not proved.

Proof pointer

Immediate from Rankin's prime-gap theorem (R. A. Rankin, J. London Math. Soc. 13 (1938), 242--247, the paper's footnote 2): the composites strictly between prp_r and pr+1p_{r+1} form a run of kk-smooth integers above kk of length pr+1−pr−1p_{r+1}-p_r-1.

Dependencies

Rankin's 1938 lower bound for large gaps between consecutive primes, with the gap located in (k,2k)(k,2k) (as stated by Erdős; the location is part of his citation of Rankin and was not checked against Rankin's paper, which is not held).

Bears on

  • Problem 961: (3) is the lower bound for f(k)f(k) that the problem page records, and (4) is Erdős's guess, on Cramér's conjecture, that f(k)=(1+o(1))(log⁡k)2f(k)=(1+o(1))(\log k)^2.