Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
For a finite sequence , counts the solutions of , and is the least such that every such sequence of integers has some with (pp. 251--252). The paper writes for absolute constants (p. 251).
Theorem 2 (p. 252).
The print states no range for or ; the proof (pp. 253--254) fixes , takes a sequence with for all and bounds its length for . As with Theorem 1, the page does not say whether is allowed in .
Source. P. Erdős, On the multiplicative representation of integers, Israel J. Math. 2 (1964), no. 4, 251--261; Theorem 2 on printed p. 252, proof on pp. 253--254.
Read depth. Claims checked: the statement and the definition of were read clause by clause on the page images. The proof (pp. 253--254) was read for its structure and not checked step by step.
Proof pointer
Pages 253--254. It suffices to show that a sequence with for all has (display (7)). The 's that are not a product of factors each exceeding (display (8)) are at most in number (display (11)), by Landau's asymptotic (10) for , the count of integers up to with at most distinct prime factors (the paper's [4]). If the remaining 's were more numerous than , sorting their factors into dyadic ranges gives a -tuple of ranges shared by more than of them (display (15)), and the paper's Lemma (p. 252) with then gives an with at least solutions. The same argument completes Theorem 1 ("which proves Theorems 1 and 2", p. 254).
A corollary follows on p. 254: if is an infinite sequence and every is a product of or fewer 's, then , by Raikov's theorem ( for infinitely many ) and Theorem 2.
Dependencies
The paper's Lemma (p. 252), proved through the corollary of Theorem 1 of the paper's [2] (Erdős, On extremal problems of graphs and generalized graphs, Israel J. Math. 2 (1964)); Landau's asymptotic (10).
Bears on
No problem page of this corpus. Theorem 3 of the same paper replaces this bound by an asymptotic; see Theorem 3.