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Statement

Setting (p. 6, display (1.4)). For V⊆UV\subseteq\mathbb U, the angle is Ang(V)=sup⁡v∈V, v≠1∣arg⁡(1−v)∣\mathrm{Ang}(V)=\sup_{v\in V,\,v\ne1}\lvert\arg(1-v)\rvert, so 0≤Ang(V)≤π/20\le\mathrm{Ang}(V)\le\pi/2, with $\mathrm{Ang}({1})=\mathrm{Ang} (\emptyset)=0$. T\mathbb T is the unit circle, and Γ(S)\Gamma(S) is the spectrum of the Theorem 1 page.

Theorem 5 (p. 9, quoted). "Suppose SS is a closed subset of U\mathbb U with 1∈S1\in S. The spectrum of SS is U\mathbb U if and only if Ang(S)=π/2\mathrm{Ang}(S)=\pi/2. If Ang(S)=θ<π/2\mathrm{Ang}(S)=\theta<\pi/2, then there exists a positive constant A(θ)A(\theta), depending only on θ\theta, such that Γ(S)\Gamma(S) is contained in a disc centered at A(θ)A(\theta) with radius 1−A(θ)1-A(\theta). In fact, A(θ)=(28/411)cos⁡2θA(\theta)=(28/411)\cos^2\theta is permissible. Thus

Γ(S)∩T={{1}if Ang(S)<π/2Tif Ang(S)=π/2."\Gamma(S)\cap\mathbb T=\begin{cases}\{1\}&\text{if }Ang(S)<\pi/2\\ \mathbb T&\text{if }Ang(S)=\pi/2.\end{cases}"

For S=[−1,1]S=[-1,1], where θ=0\theta=0, the disc is centred at 28/41128/411 with radius 383/411383/411, so Γ([−1,1])⊂[−355/411,1]\Gamma([-1,1])\subset[-355/411,1]; the paper records (p. 9) that this gives some c>−1c>-1 with Γ(S)⊂[c,1]\Gamma(S)\subset[c,1] and so generalizes Hall's theorem on Heath-Brown's conjecture. The exact value is δ1=−0.656999…\delta_1=-0.656999\ldots by Theorem 1. The paper also notes (p. 10) that $A(\theta)\le(1-\exp(-\pi\cot\theta))/2 \le\frac\pi2\cos\theta$, so A(θ)A(\theta) must tend to 00 as θ→π/2\theta\to\pi/2.

Source. Andrew Granville and K. Soundararajan, The spectrum of multiplicative functions, Ann. of Math. (2) 153 (2001), no. 2, 407--470; read as arXiv:math/9909190v1 (8 September 1999), printed page == PDF page: the angle on p. 6, Theorem 5 on p. 9, the remark on p. 10, Sections 7c and 7d on pp. 45--49. The published pagination differs and was not compared. The edition read is identified on the source card.

Read depth. Claims checked: the statement and the remarks after it were read clause by clause on the page images. The proof was not checked; the arithmetic 2⋅28/411−1=−355/4112\cdot28/411-1=-355/411 is this page's.

Proof pointer

Sections 7c and 7d (pp. 45--49). With λ=(28/411)cos⁡2θ\lambda=(28/411)\cos^2\theta the paper shows that every value σ(u)\sigma(u) of a solution of (1.5) lies within 1−λ1-\lambda of λ\lambda. With P(u)=∫0umin⁡(2,(1−Re χ(t))sec⁡2θ) dt/tP(u)=\int_0^u\min(2,(1-\mathrm{Re}\,\chi(t))\sec^2\theta)\,dt/t and u0u_0 the point where P(u0)+P(u0/2)=1P(u_0)+P(u_0/2)=1 (u0=∞u_0=\infty if there is none, p. 45), Proposition 7.5 bounds ∣σ(u)∣\lvert\sigma(u)\rvert by 1−2λ1-2\lambda for u≥u0u\ge u_0; for u≤u0u\le u_0, the inequality (7.4), the second inequality of (7.6) and (7.7) give $(\mathrm{Re},\sigma(u)-\lambda)^2+(\mathrm{Im}, \sigma(u))^2\le(1-\lambda)^2$ (p. 49). So Λ(S)\Lambda(S) lies in the disc, and Theorem 5 follows from Γ(S)⊂[0,1]×Λ(S)\Gamma(S)\subset[0,1]\times\Lambda(S) (Theorem 3′', p. 9).

Dependencies

Theorem 3′' (p. 9), Lemma 7.2 with (7.4) and (7.6) (p. 46), the inequality (7.7) (p. 47) and Proposition 7.5 (p. 48) of Section 7c of the same paper; see also Theorem 3.

Bears on

No Erdős problem page of the corpus cites this theorem.