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Statement
Page numbers are those of the author preprint named on the source card, whose five pages correspond to pp. 207--211 of the journal.
Setting (p. 1). and are integers; is the -th prime; is the number of distinct prime divisors of an integer , with ; and . When are all composite and there are distinct primes with for , Grimm's conjecture is said to hold for and . Grimm's conjecture (unrestricted) asks for such primes whenever are all composite.
Theorem 1 (p. 1, quoted). "Grimm's Conjecture holds for and for all ."
That is, for every and every such that are all composite, there are distinct primes with for . The paper records (p. 1) that .
Corollary 0.1 (p. 2). If are all composite and , then
The paper calls the assertion that (1) holds for all and with all composite a weaker version of Grimm's conjecture (p. 2).
Proof pointer
P. 2: the paper says that for Theorem 1 it suffices to prove Theorem 2, the case , for . The reduction is not spelled out; it runs as follows. A run of composites with lies inside , where is the largest prime not exceeding , so , and because composite forces ; distinct primes for that maximal run restrict to the shorter one. Corollary 0.1 follows because the distinct primes all divide the product.
Read depth
Claims checked: the setting, Theorem 1, the value of and Corollary 0.1 were read clause by clause on the page images of the print. The computation behind Theorem 2 was not rerun. Nothing here is independently reviewed.
Dependencies
Theorem 2 of the same paper.
Source. S. Laishram and T. N. Shorey, Grimm's conjecture on consecutive integers, Int. J. Number Theory 2 (2006), no. 2, 207--211, doi:10.1142/S1793042106000498; the edition read is named on the source card.
Bears on
- Problem 375: the problem asks whether the distinct primes exist for all ; Theorem 1 gives them for every and every , and says nothing for larger . The problem's claim page for this paper records it as a partial result.