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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Source. Theorem 2.1 and its proof, preprint p. 4, with the preceding paragraph on Oppenheim [6]. Read on the rendered page.

Statement

For integer sequences with every an>1a_n>1 and bn=O(an)b_n=O(a_n), if some irrational α\alpha is a limit point of the ratios bn/anb_n/a_n, then the (convergent) series S=∑n≥1bn/(a1⋯an)S=\sum_{n\ge1}b_n/(a_1\cdots a_n) is irrational.

Corollary 2.1 (p. 4): if lim⁡bn/an\lim b_n/a_n exists and is irrational, SS is irrational. Oppenheim (Amer. Math. Monthly 61 (1954), 235--241) had the same conclusion under 0≤bn<an0\le b_n<a_n.

Proof (p. 4), summarized

If S=r/qS=r/q, then qRn∈ZqR_n\in\mathbb{Z} for all nn (Lemma 2.1). Along a subsequence bnk/ank→αb_{n_k}/a_{n_k}\to\alpha; since α∉Q\alpha\notin\mathbb{Q}, ank→∞a_{n_k}\to\infty. From Rnk=bnk/ank+Rnk+1/ankR_{n_k}=b_{n_k}/a_{n_k}+R_{n_k+1}/a_{n_k} and ∣Rnk+1∣≤M(1+1/2+1/4+⋯ )=2M|R_{n_k+1}|\le M(1+1/2+1/4+\cdots)=2M (with ∣bn/an∣≤M|b_n/a_n|\le M), the integers qRnkqR_{n_k} tend to qαq\alpha, so α\alpha is rational, a contradiction. ■\blacksquare

Role

Not used for the prime series of this library's problems: for an=2a_n=2 and bn=pnb_n=p_n the hypothesis bn=O(an)b_n=O(a_n) fails, and for an=na_n=n, bn=pnb_n=p_n the ratios pn/np_n/n tend to infinity. Recorded for the card's coverage.

Bears on. No catalog problem directly.