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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Section I.11 (printed p. 138, in Hungarian): let a1<a2<⋯<aZ≤na_1<a_2<\dots<a_Z\le n be a sequence such that the products ∏i=1Zaiεi\prod_{i=1}^Z a_i^{\varepsilon_i}, εi=0\varepsilon_i=0 or 11, are all distinct. "I conjectured, in I, that

Z<π(n)+cn1/2/log⁡n.(1)Z<\pi(n)+cn^{1/2}/\log n. \tag{1}

I have since proved (1)." (The Hungarian: "Sejtettem, I-ben, hogy ... (1)-et azóta bebizonyítottam.") Paper I is the 1962 first installment of the series.

Source. P. Erdős, Számelméleti megjegyzések, V. Extremális problémák a számelméletben, II, Mat. Lapok 17 (1966), 135--155; Section I.11 on printed pp. 138--141 (PDF pp. 4--7 of the Rényi archive's 21-page scan), read on the page images; the site's key for Problem 795 cites the paper without a page.

Read depth. Claims checked: the statement (1) and its two sentences were read clause by clause on the page image of p. 138. The proof sketch (displays (2)--(12), pp. 138--140) was read for its structure and not checked step by step.

Proof pointer

Pages 138--140. Split the aia_i into two classes: first those all of whose prime factors are below n1/2n^{1/2}; claim (2) r<c1n1/2/log⁡nr<c_1n^{1/2}/\log n for their number rr. Their 2r2^r subset products (3) are distinct and each is of the form U⋅VU\cdot V with UU built from the primes ≤n1/3\le n^{1/3} and VV from the primes in (n1/3,n1/2](n^{1/3},n^{1/2}]; the exponent of a prime pp in UU takes at most 1+rlog⁡n/log⁡p<r21+r\log n/\log p<r^2 values (4), so UU has at most (r2)π(n1/3)<n2n1/3(r^2)^{\pi(n^{1/3})}<n^{2n^{1/3}} choices (5), and with ∑αi≤2r\sum\alpha_i\le2r (6) the arithmetic-geometric mean inequality bounds the choices of VV by ((2r+s)/s)s((2r+s)/s)^s (7), ss the number of primes in the range; the product (8) is below 2r2^r if (2) fails, a contradiction. The second class consists of numbers p⋅bp\cdot b with a prime p>n1/2p>n^{1/2}; with tit_i the number of members sharing the prime pip_i, their number is at most π(n)+∑ti\pi(n)+\sum t_i (9), and (1) follows from (10) T=∑ti<c3n1/2/log⁡nT=\sum t_i<c_3n^{1/2}/\log n, proved by the same counting of the 2T2^T products (11) of the pibi(k)p_ib_i^{(k)}.

Dependencies

The prime number theorem for s<c2(n/log⁡n)1/2s<c_2(n/\log n)^{1/2}; the arithmetic-geometric mean inequality. Nothing else is cited in the section.

Bears on

  • Problem 795: the bound the site's commentary attributes to [Er66], g(n)≤π(n)+O(n1/2/log⁡n)g(n)\le\pi(n)+O(n^{1/2}/\log n), with its proof sketch. The problem's own question is display (13) on p. 140, max⁡Z=π(n)+π(n1/2)+o(n1/2/log⁡n)\max Z=\pi(n)+\pi(n^{1/2})+o(n^{1/2}/\log n), which Erdős calls not impossible while saying he cannot decide it; after a construction made with Pósa (14), he gives the lower bound (15) from sets with distinct subset sums and adds that equality perhaps holds in (15).