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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

On p. 89, for the sequence (1.1), u1=mu_1=m, un+1=⌊2 (un+1/2)⌋u_{n+1}=\lfloor\sqrt2\,(u_n+1/2)\rfloor with m∈Z+m\in\mathbb Z^+:

Fact 1 (Graham--Pollak). For the starting value m=1m=1 and every n≥1n\ge1, the second difference

dn=u2n+1−2u2n−1(1.2)d_n=u_{2n+1}-2u_{2n-1} \tag{1.2}

equals the nnth digit of the binary expansion 2=(1.011010100…)2\sqrt2=(1.011010100\ldots)_2.

The same page reports Graham and Pollak's closed form un=⌊τ(2(n−1)/2+2(n−2)/2)⌋u_n=\lfloor\tau(2^{(n-1)/2}+2^{(n-2)/2})\rfloor for n≥2n\ge2, where τ\tau is the mmth smallest real number in {1,2,3,…}∪{2,22,32,…}\{1,2,3,\ldots\}\cup\{\sqrt2,2\sqrt2,3\sqrt2,\ldots\}, and attributes the recurrence's origin to Hwang and Lin's analysis of the Ford--Johnson sorting algorithm. With u1=1u_1=1 the sequence is $1,2,3,4,6,9,13,19,27,38,54,77, 109,\ldots$ (OEIS A001521, as the author's 2005 paper records), and d1=u3−2u1=1d_1=u_3-2u_1=1, d2=u5−2u3=0d_2=u_5-2u_3=0, d3=u7−2u5=1d_3=u_7-2u_5=1, d4=u9−2u7=1d_4=u_9-2u_7=1 (checked here by hand against 2=1.0110…\sqrt2=1.0110\ldots in binary, where the digits are counted from the leading digit).

Source. Thomas Stoll, On a problem of Erdős and Graham concerning digits, Acta Arith. 125 (2006), no. 1, 89--100; Fact 1 on printed p. 89 (PDF p. 1 of the retained journal file), read on the rendered page image. The original, R. L. Graham and H. O. Pollak, Note on a nonlinear recurrence related to 2\sqrt2, Math. Mag. 43 (1970), no. 3, 143--145, is held and filed as graham_pollak_1970_note_nonlinear_recurrence_related_sqrt2; the identity is announced there on printed p. 143 (PDF p. 2 of the retained JSTOR scan) and stated for m=1m=1 as immediate from the closed form on printed p. 145 (PDF p. 4), both read clause by clause on the page images and paged on binary_digits_p143. The artifact is identified in the source digest.

Read depth. Claims checked: the statement and the surrounding paragraph were read clause by clause on the page image; the first four digits were recomputed here. Of the 1970 note, the announcement on printed p. 143 and the closing statement for m=1m=1 on printed p. 145 were read clause by clause on the page images; its proof of the closed form (pp. 143--145) was not read for this page and is recorded on the held card. Stoll's paper derives the identity as the case w=2w=\sqrt2, ε=1/2\varepsilon=1/2, (m,l,k)=(1,0,0)(m,l,k)=(1,0,0) of his Theorem 3.3 (p. 93).

Proof pointer

The 1970 note, held and filed as graham_pollak_1970_note_nonlinear_recurrence_related_sqrt2: the identity is announced on printed p. 143 and follows on p. 145 from the closed form of its Theorem, as paged on binary_digits_p143. Within Stoll's paper, Fact 1 is a special case of Theorem 3.3, proved in Section 4 by induction on closed forms; the paper notes that for w=2w=\sqrt2 the binary digits are obtained whenever 1/3≤ε<2/31/3\le\varepsilon<2/3.

Dependencies

None beyond the definition of the sequence.

Bears on

  • Problem 482: the identity stated in the problem's first paragraph, attributed by the site to Graham and Pollak [GrPo70]; held here through Stoll's restatement.