Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Statement
Notation (p. 125): is the set where .
Theorem 11 (p. 143). "If the lie in a disk of radius
then the set is convex."
Numerically . The paper adds (p. 145) that the example with large shows that the theorem fails if is replaced by a constant greater than ; it does not settle the constants between and . The theorem places no condition on the center of the disk; the proof takes it at the origin (p. 143).
Source. P. Erdős, F. Herzog, G. Piranian, Metric properties of polynomials, J. Analyse Math. 6 (1958), 125--148, doi:10.1007/BF02790232; Theorem 11 on p. 143, its proof on pp. 143--145 and the example on p. 145. The copy read is identified on the source card.
Read depth. Claims checked: the statement and the example were read on the page images of pp. 143 and 145 on 2026-10-08; the proof was read for structure, not checked. Nothing here is independently reviewed.
Proof pointer
Pages 143--145. With the zeros in , the proof shows that the lemniscate has no point of inflection when . At a supposed inflection point , expand along the curve to second order in the arc parameter : the first-order term vanishes because is constant on the curve, which turns the second-order coefficient into , with and the angle between the line and the tangent. Since , all the lie within of each other, and with the vanishing first-order term this puts every within of . When , that is , the coefficient is positive, contradicting along the curve.
Dependencies
None.
Bears on
- #1047: the paper calls Grunsky's question, Problem 16, "related to our theorem" (p. 145). The theorem concerns the level with all zeros in one small disk, the problem the loops around distinct zeros at a small level; the paper derives neither from the other.