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Statement

Notation (pp. 125, 139): EE is the set where ∣f∣<1|f|<1; Dˉr\bar D_r is the closed disk ∣z∣≤r|z|\le r; S(r,n)S(r,n) is the maximum of the sum of the diameters of the components of EE over monic ff of degree nn with zeros in Dˉr\bar D_r, and S(r)S(r) the supremum of S(r,n)S(r,n) over n=1,2,…n=1,2,\ldots.

Theorem 9 (p. 140). "The function S(r)S(r) has the following properties: if 0≤r≤1/20\leq r\leq1/2, then S(r)=21+r2S(r)=2\sqrt{1+r^2}; if ε>0\varepsilon>0 and bb is sufficiently small, then S(1−b)>(1/2−ε)(1−e−1)log⁡1/bS(1-b)>(1/2-\varepsilon)(1-e^{-1})\log1/b."

So S(r)S(r) is finite and explicit for small rr and tends to infinity as rr increases to 11. The paper introduces S(r)S(r) (p. 139) because S(r,n)S(r,n), for n≥3n\ge3, "appears to be a discontinuous function of rr, at r=1r=1"; for unrestricted zeros it conjectures there that the sum of the diameters of the components of EE never exceeds n21/nn2^{1/n}, the value for zn−1z^n-1.

Source. P. Erdős, F. Herzog, G. Piranian, Metric properties of polynomials, J. Analyse Math. 6 (1958), 125--148, doi:10.1007/BF02790232; Theorem 9 on p. 140, its proof on pp. 140--141. The copy read is identified on the source card.

Read depth. Claims checked: the statement and the definitions of S(r,n)S(r,n) and S(r)S(r) were read on the page images of pp. 139--140 on 2026-10-08; the proof was read for structure, not checked. Nothing here is independently reviewed.

Proof pointer

Pages 140--141. For r≤1/2r\le1/2, EE contains the disk of radius 1/21/2 and is star-shaped, so the sum is the diameter of EE; projecting the zeros onto a line through a longest chord of Eˉ\bar E can only enlarge the diameter, which reduces the first property to Theorem 2. For the lower bound, Q(w)=(w2−s2)q(w+s)Q(w)=(w^2-s^2)^q(w+s) with s=exp⁡(−c3/q2)s=\exp(-c_3/q^2) has a component of E(Q)E(Q) containing [s/q,s][s/q,s] and avoiding the line Re⁡w=s/2q\operatorname{Re}w=s/2q; then f(z)=Q(zn)f(z)=Q(z^n) has its zeros on ∣z∣=s1/n|z|=s^{1/n} and nn separate components each containing a segment longer than r(1−q−1/n)r(1-q^{-1/n}). Taking n=[log⁡q]n=[\log q] and 1−b=exp⁡(−c3/(nq2))1-b=\exp(-c_3/(nq^2)) gives the bound along a sequence bqb_q with bq+1/bq→1b_{q+1}/b_q\to1.

Dependencies

Theorem 2.

Bears on

No problem in the catalog is recorded here as concerning this theorem. It sums component diameters, while Problem 7 (#1048) asks for one large component.