Wiki
Wiki

Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

Updated


Statement

Notation as on the Statement (I) page; the nonnegative zeros of pnp_n are j=0,1,…,nj=0,1,\ldots,n and those of qnq_n are j=0,1,…,n+1j=0,1,\ldots,n+1.

Slopes at the zeros (Section 4, pp. 297--298). With 0!=10!=1,

∣pn′(j)∣=(n+j)! (n−j)!,j=0,1,…,n,(16)|p'_n(j)|=(n+j)!\,(n-j)!,\qquad j=0,1,\ldots,n, \tag{16} ∣qn′(j)∣=(n+j)! (n+1−j)!,j=0,1,…,n+1.(18)|q'_n(j)|=(n+j)!\,(n+1-j)!,\qquad j=0,1,\ldots,n+1. \tag{18}

Hence (p. 297, (17))

∣pn′(j+1)∣−∣pn′(j)∣=(2j+1)(n+j)! (n−j−1)!>0,j=0,1,…,n−1,|p'_n(j+1)|-|p'_n(j)|=(2j+1)(n+j)!\,(n-j-1)!>0,\qquad j=0,1,\ldots,n-1,

and (p. 298, (19))

∣qn′(j+1)∣−∣qn′(j)∣=(2j)(n+j)! (n−j)!>0,j=1,…,n.|q'_n(j+1)|-|q'_n(j)|=(2j)(n+j)!\,(n-j)!>0,\qquad j=1,\ldots,n.

So ∣pn′(j)∣|p'_n(j)| increases for j=0,…,nj=0,\ldots,n, and ∣qn′(j)∣|q'_n(j)| increases for j=1,…,n+1j=1,\ldots,n+1, while ∣qn′(0)∣=∣qn′(1)∣=n! (n+1)!|q'_n(0)|=|q'_n(1)|=n!\,(n+1)!, for each fixed nn.

Statement (III) (p. 298). The sequences {∣pn′(j)∣}\{|p'_n(j)|\}, j=0,…,nj=0,\ldots,n, and {∣qn′(j)∣}\{|q'_n(j)|\}, j=1,…,n+1j=1,\ldots,n+1, are each absolutely monotonic.

Here a sequence {aj}\{a_j\} is absolutely monotonic when every defined difference is non-negative: Δmaj≥0\Delta^m a_j\ge0 for all mm and jj, where Δ0aj=aj\Delta^0a_j=a_j and Δm+1aj=Δmaj+1−Δmaj\Delta^{m+1}a_j=\Delta^m a_{j+1}-\Delta^m a_j (p. 298). For pnp_n this is the inequality

Δm{(n+j)! (n−j)!}≥0,j=0,…,n;m=0,…,n−j,(20)\Delta^m\{(n+j)!\,(n-j)!\}\ge0,\qquad j=0,\ldots,n;\quad m=0,\ldots,n-j, \tag{20}

and the paper shows it with strict inequality. Remark (i) (p. 299) says that similar results hold for these sequences taken at fixed jj as nn varies.

Read depth. Claims checked: (16)--(20) and (III) were read on the page images of pp. 297--299. The proofs were followed but not checked step by step.

Proof pointer

Pp. 297--299. (16) comes from the product rule applied to (1): at an interior zero jj only one term survives, and the two remaining products evaluate to (2j)!(2j)! and ∏k=j+1n(k2−j2)\prod_{k=j+1}^{n}(k^2-j^2), whose product is (n+j)!(n−j)!(n+j)!(n-j)!; the cases j=0,1,nj=0,1,n are checked directly. (18) follows from qn′=(x−n−1)pn′+pnq'_n=(x-n-1)p'_n+p_n, with qn′(n+1)=pn(n+1)=(2n+1)!q'_n(n+1)=p_n(n+1)=(2n+1)!. For (20) the paper proves by induction that Δm{(n+j)!(n−j)!}\Delta^m\{(n+j)!(n-j)!\} equals (n+j)!(n−j−m)!(n+j)!(n-j-m)! times a polynomial in j,m,nj,m,n with non-negative integer coefficients, not all zero; the case of qnq_n is said to follow in the same fashion. Remark (ii) (p. 299) reports D. J. Newman's observation that a beta function integral for these differences makes (20) obvious.

Dependencies

The definitions (1) and (2).

Bears on

None recorded.