Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
Setting (p. 113). is the number of solutions of with prime, as for Theorem 1, which gives for infinitely many .
(a) The upper bound (p. 115, quoted). "It can be conjectured that ." The paper adds that this, if true, is probably rather deep.
(b) The integers (p. 115). The paper cannot prove that, for all sufficiently large , the integers
are not all prime. For all of them are prime; the paper reports from the prime tables that no other in has this property, and states (quoted) "It seems likely that 105 is the largest exceptional integer."
(c) A generalization of Theorem 1 (p. 115). Erdős believes the following holds: for every constant and every sufficiently large , if with , then some has more than representations . The paper calls this a generalization of Theorem 1.
Scope
These are problems the paper poses; it proves none of them. Statement (a) is the pointwise bound that Theorem 1 complements from below; Theorem 2 bounds only on average.
Read depth. Claims checked: the three statements were read clause by clause on p. 115 of the print, and the product $3\cdot5^2\cdot11\cdot13\cdot19 =203775$ was checked.
Source. P. Erdős, On integers of the form and some related problems, Summa Brasil. Math. 2 (1950), fasc. 8, 113--123; the edition read is named on the source card.
Bears on
- Problem 236: statement (a) is the problem's question, posed here as a conjecture; the paper proves nothing on it.
- Problem 1142: statement (b), with , ranges over the same powers as the problem. The paper records and a search to and conjectures that is the largest such , which is the problem's question whether any exists; it proves nothing on it.
- Problem 237: statement (c) is a form of the problem's question for finite sets, with the hypothesis in place of the problem's $\lvert A\cap{1,\ldots,N}\rvert\gg \log N$; the paper calls it a generalization of Theorem 1, which treats the powers of , and proves nothing on it beyond that theorem.