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Source. Proposition 4.1, p. 14, with its proof on pp. 14--16, of Ben Green and Imre Z. Ruzsa, On the arithmetic Kakeya conjecture of Katz and Tao, arXiv:1712.02108 (2017); the edition read is named on the source card.
Statement
Notation. (p. 5) is the size of the smallest set $A\subset\mathbb Z$ containing an arithmetic progression of length and common difference for different values of .
Proposition 4.1 (p. 14). Let be the minimum, over all intervals of length and all choices of primes , of . Then
In particular Conjectures 1' and 5 (see Theorem 1.1) are equivalent.
Combined with Theorem 1.2 and (p. 6), the upper bound gives as , with absolute; the paper states the consequence as in Conjecture 5 (p. 4).
Proof pointer
Lower bound: the multiples of the in an extremal interval contain a -term progression with difference for each . Upper bound: take an extremal set of positive integers with progressions of differences ; the theorem of Green and Tao cited as the paper's reference [10, Theorem 1.2] gives with all of prime in a short range ; set , choose by the Chinese remainder theorem with , and check that an interval of length placed at meets each exactly in the progression , , inside , a set of at most elements. The remark after the proof (p. 16) says simpler arguments would do at the cost of logarithmic losses.
Read depth
Claims checked: the definition of , the statement and the proof on pp. 14--16 were read clause by clause on the print. The cited theorem of Green and Tao was not read. Nothing here is independently reviewed.
Dependencies
External input: Green and Tao, the paper's reference [10], Theorem 1.2.
Bears on
- Problem 1143: for an integer , is the least value of that problem's count over primes. The proposition places it between and , so the problem's least count for fixed integer is, up to a factor , the arithmetic Kakeya quantity ; with Theorem 1.2 it is at most . It settles no exact value or order of the count.