Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
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Statement
is the number of divisible by no element of .
Lemma 2.8 (printed p. 264). Let be a set of integers such that the least common multiple of and exceeds for all with . If , , then
Remark (p. 264). The author records two questions as not known: whether must hold for all sets with this least-common-multiple property and ; and whether can occur for large , the only example known being for or .
After the proof (p. 265) the author states, without proof, that he can improve the bound to , and conjectures that it holds with .
Source. I. Z. Ruzsa, On the small sieve. II. Sifting by composite numbers, J. Number Theory 14 (1982), 260–268; Lemma 2.8 and the Remark on printed p. 264, the proof on p. 264, the improved bound on p. 265. The edition is identified in the source digest.
Read depth. Claims checked: the statement, the Remark and the sentence after the proof were read on the page images. The proof was not checked.
Proof pointer
The least-common-multiple property kills every term of the inclusion–exclusion formula beyond the first, so for . Comparing with for a real bounds the number of elements of in by , which leads to ; the choice finishes.
Dependencies
None.
Bears on
- Problem 542: the problem's sets without the element are those of the lemma, and its first question asks whether their reciprocal sum is at most . The lemma bounds the reciprocal sum by in terms of the proportion left unsifted, so sets that leave few integers unsifted have reciprocal sum at most about . For above the bound exceeds , so the lemma does not answer the first question, which Schinzel and Szekeres answered. The Remark records as unknown whether the sum is below for all such sets and large , the speculation the problem page records from Erdős.