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Statement

The notation rr-graph, independent, Er(n,k)E_r(n,k) and er(n,k)e_r(n,k) is that of the Theorem 1 page; deg⁡v\deg v is the number of edges containing vv.

Theorem 2 (p. 30, quoted). "Let G=(V,T)G=(V,T) be an rr-graph with r⩾2r\geqslant2, k⩾1k\geqslant1 and ∣V∣=n>2r3(k+2)|V|=n>2r^3(k+2). Suppose GG contains at most kk independent rr-tuples. If

deg⁡v>d=dr(n,k)=(n−1r−1)−(n−kr−1)+r3n−k+1(n−k−1r−2)\deg v>d=d_r(n,k)=\binom{n-1}{r-1}-\binom{n-k}{r-1}+\frac{r^3}{n-k+1}\binom{n-k-1}{r-2}

for every v∈Vv\in V then G⊂Er(n,k)G\subset E_r(n,k)."

The paper calls this its main aim (p. 26): a condition forcing k+1k+1 independent edges unless G⊂Er(n,k)G\subset E_r(n,k), through the degree of every vertex instead of the number of edges. The minimum degree of Er(n,k)E_r(n,k) is (n−1r−1)−(n−k−1r−1)=er−1(n−1,k)\binom{n-1}{r-1}-\binom{n-k-1}{r-1}=e_{r-1}(n-1,k), and the paper states as following from Theorem 2 that on n>2r3(k+2)n>2r^3(k+2) vertices every degree greater than this forces k+1k+1 independent rr-tuples, with Er(n,k)E_r(n,k) showing that the condition cannot be weakened (pp. 26--27). That dr(n,k)d_r(n,k) lies below er−1(n−1,k)e_{r-1}(n-1,k) in this range is a one-line check not printed: the two differ by (1−r3n−k+1)(n−k−1r−2)\left(1-\frac{r^3}{n-k+1}\right)\binom{n-k-1}{r-2}. The paper also notes (p. 31) that the number of edges guaranteed by the degree condition is less than fr(n,k)f_r(n,k), so Theorem 2 does not follow directly from Theorem 1.

Source. B. Bollobás, D. E. Daykin and P. Erdős, Sets of independent edges of a hypergraph, Quart. J. Math. Oxford Ser. (2) 27 (1976), 25--32, as identified on the source card: Theorem 2 on p. 30, with the consequence on pp. 26--27.

Read depth. Claims checked: the statement was read clause by clause on the print. The proof (pp. 30--31) was read for its structure only; nothing here is independently reviewed.

Proof pointer

Pages 30--31, by induction on kk. Part (b) of the paper's Lemma 1 (p. 27) gives a vertex vv of degree at least ∣T∣/(rk)>nd/(r2k)|T|/(rk)>nd/(r^2k). For k=1k=1 part (a) then shows that G−vG-v has no edge. For k>1k>1 the degrees in H=G−vH=G-v exceed dr(n−1,k−1)d_r(n-1,k-1), so if HH has at most k−1k-1 independent edges the induction hypothesis gives a covering (k−1)(k-1)-set, to which vv is added; if HH has kk independent edges, part (a) bounds deg⁡v\deg v above, and the inequalities (1) and (2) of p. 27 contradict n>2r3(k+2)n>2r^3(k+2).

Bears on

The theorem bounds degrees, not the number of edges, and the paper does not relate it to the extremal edge count; the card records no problem it bears on.