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Source. Theorem 1, pp. 128-129, of P. Frankl, "On families of finite sets no two of which intersect in a singleton," Bull. Austral. Math. Soc. 17 (1977), no. 1, 125-134, doi:10.1017/S0004972700025521. Pages are the journal's own, as on the source card.

Setting

XX is a set of nn elements. A family F\mathcal F of kk-subsets of XX is an (n,L,k)(n,L,k)-system if any two different members meet in a number of elements belonging to LL (p. 125), and Fx={F−x:x∈F∈F}\mathcal F_x=\{F-x : x\in F\in\mathcal F\}. The paper introduces Theorem 1 (p. 128) as a slightly weaker result which implies the conjecture of Erdős and Sós.

Statement

Theorem 1 (pp. 128-129). Let F\mathcal F be an (n,{0,2,3,…,k−1},k)(n,\{0,2,3,\ldots,k-1\},k)-system of subsets of XX, with n>n0(k)n>n_0(k). Then one of the following cases occurs:

(i) ∣F∣<(n−2k−2)\lvert\mathcal F\rvert<\binom{n-2}{k-2};

(ii) for some x≠yx\ne y in XX, F\mathcal F is the family of all kk-subsets of XX containing both xx and yy;

(iii) for some x∈Xx\in X, ∣Fx∣<(n−3k−3)\lvert\mathcal F_x\rvert<\binom{n-3}{k-3};

(iv) for some x≠yx\ne y in XX, fewer than (n−3k−3)+(n−4k−3)\binom{n-3}{k-3}+\binom{n-4}{k-3} members of F\mathcal F meet {x,y}\{x,y\}.

The printed hypothesis does not repeat k≥4k\ge4, and n0(k)n_0(k) is left implicit. Lemmas 1 and 2 (pp. 126-127), on which the proof rests, assume k≥4k\ge4 (Lemma 3, pp. 127-128, does not), and the proof uses k≥4k\ge4 on p. 129.

Read depth. Claims checked: the statement was read clause by clause on the print and the proof read through.

Proof pointer

Pages 129-132, by contradiction. Assuming (iii) and (iv) fail, the paper uses Lemmas 1 to 3 on the minimal sunflower kernels of the links to show that each link's kernels form a single pair or a single point. Then F\mathcal F lies in a family built from disjoint pairs {xi,yi}\{x_i,y_i\} and classes ZiZ_i, and a count by induction on the number of pairs gives (i) or (ii).

Bears on

  • Problem 702: the structural step from which Theorem 2 derives the problem's corrected Statement; on its own it does not give the bound.