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Source. Published pp. 275–277, Theorem 6.1 (PDF).
Statement. For there is such that, for and ,
Proof. All estimates below are uniform in . We use the proved uniform factorial estimates, so perturbing a bounded number of cell sizes by at most changes logarithms of counts by . Choose a small positive depending on , then a much smaller , and finally small enough for the uses below. Set , , and . We work first with large , so these integers are positive and all indicated cells are feasible.
Each family has density at least . The incidence graph of -sets and -sets with has degree at . By Lemma 4.1, for each there is a family of at least such sets , each incident with at least
members of . At least half of has a member of at exchange distance at most . Otherwise the bad half and avoid intersection ; Corollary 1.6 contradicts their density lower bounds when is sufficiently small in terms of . Its buffer is positive: the upper intersection gap is , and the lower feasibility gaps are at least a fixed multiple of . The slice-separation lemma also proves this proximity directly.
For each such , pad to a set of size . At most different yield a fixed . We obtain a family with
For every , each has at least members satisfying .
For such , count ordered pairs with
call their number . For a fixed pair with intersection , its four atoms have sizes . The number of all possible for this pair is exactly
where an infeasible binomial coefficient is zero. All selected or omitted parts in (4) have size at most , so the entropy estimates give . Consequently .
Assume the conclusion of (1) fails. Use the exact identity
and (3)–(4). First choosing so that its entropy loss is less than , then smaller, and finally large, gives some with
By (2) and the same entropy estimates, . Thus (6) is less than when are small and is large. Delete from each local family all vertices incident with one of these counted pairs. Each side loses at most vertices, so the remaining families each have size at least , and no counted pair remains.
Let consist of the subsets whose fiber in has size at least . Fibers below that size contribute at most altogether. Each fiber has at most members. Therefore
The first families have densities in , and the residual fibers have the same type of density in . Choose sufficiently small after . Theorem 1.4 on gives with ; its two interior gaps are positive fixed multiples of and . Apply Theorem 1.4 once more to the two residual fibers, obtaining residual intersection . The reconstructed pair then has total intersection and inner intersection , contradicting its deletion. This proves (1) for all large .
For finitely many remaining , choose small enough that the input density product forces both families to be full. This is possible because all relevant layers are finite. Then the full count in (1) proves the conclusion.
Source precision. The sum over the selected family of 's on p. 276 is bounded above by the unrestricted count (4); equality need not hold for that selected family. On p. 277 the displayed lower bound for loses the factor : the fiber-counting argument gives the denominator in (7), not . The corrected bound is essential to the following application of Theorem 1.4. Floors and the order of parameter choices are explicit here.
Dependencies. lemma_4_1, corollary_1_6, theorem_1_4, entropy_estimates, slice_separation.