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Source. Section 2 and the opening paragraphs of Sections 3–4, printed pp. 1323–1325 (published PDF).

Let SS be a finite set and let A=(Ai)i∈I\mathcal A=(A_i)_{i\in I} be a finite indexed family of subsets of SS. Equal subsets at different indices remain different family members. For J⊆IJ\subseteq I, write

A(J)=⋃i∈JAi.A(J)=\bigcup_{i\in J}A_i.

Let p=(pi)i∈Ip=(p_i)_{i\in I} have nonnegative integer coordinates and put

p(J)=∑i∈Jpi,N=p(I).p(J)=\sum_{i\in J}p_i, \qquad N=p(I).

A pp-transversal of A\mathcal A is a subset X⊆SX\subseteq S for which there are pairwise disjoint sets Xi⊆AiX_i\subseteq A_i such that

X=⨆i∈IXi,∣Xi∣=pi.X=\bigsqcup_{i\in I}X_i, \qquad |X_i|=p_i.

To represent the multiplicities, define the replicated index set and family

Ip={(i,h):i∈I,1≤h≤pi},Ai,hp=Ai.I^p=\{(i,h):i\in I, 1\le h\le p_i\}, \qquad A^p_{i,h}=A_i.

Thus pp-transversals are exactly the ranges of full transversals of the replicated family Ap\mathcal A^p. Coordinates with pi=0p_i=0 create no copy. If I=∅I=\varnothing, the empty set is the unique pp-transversal.

For an integer k≥0k\ge0, a kk-transversal is the support

X={yi:i∈I}X=\{y_i:i\in I\}

of an indexed assignment i↦yi∈Aii\mapsto y_i\in A_i for which every fiber has size at most kk:

1≤∣{i:yi=x}∣≤k(x∈X).1\le |\{i:y_i=x\}|\le k \qquad(x\in X).

The assignment, rather than its support, records repeated representatives. This makes precise the source's set Y={Yi,i∈I}Y=\{Y_i,i\in I\} “of not necessarily distinct elements” (p. 1325). For k=0k=0, such an assignment exists exactly when II is empty.

When k≥1k\ge1, put

Sk=S×[k],π:Sk⟶S,π(x,h)=x.S^k=S\times[k], \qquad \pi:S^k\longrightarrow S, \qquad \pi(x,h)=x.

An indexed assignment with multiplicity at most kk lifts to distinct labeled copies in SkS^k: for each xx, label its at most kk occurrences injectively by 1,…,k1,\ldots,k. Conversely, a transversal in the copied sets Ai×[k]A_i\times[k] projects to a kk-transversal.

All matroids in this source unit are finite. Their rank functions are denoted by rr. A base is a maximal independent set; all bases have the rank of the ground set. The empty set has rank zero.