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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Conventions (p. 111). A set-mapping of type 1 on SS assigns to each point x∈Sx\in S a set f(x)⊆Sf(x)\subseteq S with x∉f(x)x\notin f(x) (the paper's original notion, a mapping on the one-element subsets); order nn means ∣f(x)∣<n\lvert f(x)\rvert<n for every xx. A set S′⊆SS'\subseteq S is free when y∉f(x)y\notin f(x) for all x,y∈S′x,y\in S'.

Lemma 4 (p. 119). Let SS be a set of power m≥ℵ0m\ge\aleph_0, let n<mn<m, and let ff be a set-mapping of SS of type 1 and order nn. Then SS is the union of at most nn free sets.

Source. P. Erdős and A. Hajnal, On the structure of set-mappings, Acta Math. Acad. Sci. Hungar. 9 (1958), 111--131: Lemma 4 on p. 119, with footnote 9 citing G. Fodor, Proof of a conjecture of P. Erdős, Acta Sci. Math. Szeged 14 (1951--1952), 219--227, Theorem 1. The edition is the one identified on the source card.

Read depth. Claims checked: the statement and the definitions it uses were read on the printed pages. The paper gives no proof; it cites Fodor's theorem.

Proof pointer

No proof in the paper: Lemma 4 is stated as a theorem of G. Fodor, with the reference above. The paper uses it in the proof of Theorem 3 (p. 119).

Bears on

No Erdős problem page directly; the paper uses it as a tool for Theorem 3.