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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Statement

Conventions (pp. 111--112, as on the Theorem 1 and Theorem 2 pages): a set-mapping of type ω\omega and order 2 on SS sends each finite X⊆SX\subseteq S to a set f(X)f(X) of at most one point, disjoint from XX; a set S′S' is free when f(X)∩S′=∅f(X)\cap S'=\varnothing for every finite X⊆S′X\subseteq S'.

Problem 1 (p. 113, quoted). "(ℵω,2,ω)→ℵ0(\aleph_\omega, 2, \omega)\to\aleph_0?"

That is: must every set-mapping of type ω\omega and order 2 on a set of power ℵω\aleph_\omega have an infinite free set? The paper calls it the simplest unsolved problem here; ℵω\aleph_\omega is the first cardinal that Theorem 2 does not cover. The paper notes in the same place that (ℵω,2,ω)↛ℵ1(\aleph_\omega,2,\omega)\not\to\aleph_1 follows easily from Theorem 2. Under its hypothesis (**) (p. 112), a two-valued measure on a strongly inaccessible cardinal, Theorem 7 (p. 123) gives (m,n,ω)→m(m,n,\omega)\to m for strongly inaccessible m>ℵ0m>\aleph_0 and n<mn<m, a positive result at much larger cardinals.

Source. P. Erdős and A. Hajnal, On the structure of set-mappings, Acta Math. Acad. Sci. Hungar. 9 (1958), 111--131: Problem 1 and the remark after it on p. 113. The edition is the one identified on the source card.

Read depth. Claims checked: the problem, the remark after it and the definitions they use were read on the printed pages.

Bears on

  • Problem 623: the problem asks whether every map ff from the finite subsets of a set XX of power ℵω\aleph_\omega to XX with f(A)∉Af(A)\notin A has an infinite independent YY, one with f(B)∉Yf(B)\notin Y for every finite B⊆YB\subseteq Y. It has the same answer as Problem 1 (an observation of this page). Such an ff gives the set-mapping A↦{f(A)}A\mapsto\{f(A)\} of type ω\omega and order 2 with the same free sets, so a positive answer to Problem 1 answers Problem 623 positively. Conversely, a set-mapping gg of type ω\omega and order 2 with no infinite free set gives such an ff, taking the point of g(A)g(A) when there is one and any point outside the finite AA otherwise; every free set of ff is free for gg, so ff has no infinite independent set. The paper leaves Problem 1 open.