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Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.

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Source. P. Erdős and A. Hajnal, On chromatic number of graphs and set-systems, Acta Math. Acad. Sci. Hungar. 17 (1966), 61--99, doi:10.1007/BF02020444; Problem 5.10 and the unnumbered assertion after it, p. 73. The edition read is identified in the source digest.

Statement

Problem 5.10 (p. 73). Assuming CH, is there a graph G\mathcal G with α(G)=ω1\alpha(\mathcal G)=\omega_1 vertices and Chr⁡(G)=ω1\operatorname{Chr}(\mathcal G)=\omega_1 that contains neither a [ ⁣[ω,ω] ⁣][\![\omega,\omega]\!] (complete bipartite, both parts countably infinite) nor a triangle [ ⁣[3] ⁣][\![3]\!]?

The paper says that an affirmative answer would follow from the following assertion, printed without a number:

Every graph G\mathcal G with α(G)=α≥ω\alpha(\mathcal G)=\alpha\geq\omega, Chr⁡(G)=α\operatorname{Chr}(\mathcal G)=\alpha contains a subgraph G′\mathcal G' with α(G′)=α\alpha(\mathcal G')=\alpha, Chr⁡(G′)=α\operatorname{Chr}(\mathcal G')=\alpha such that [ ⁣[3] ⁣]⊈G′[\![3]\!]\not\subseteq\mathcal G'.

(p. 73, quoted with the print's symbols.) The authors state that they do not know whether the assertion is true or false for any infinite α\alpha, even with [ ⁣[3] ⁣][\![3]\!] replaced by [ ⁣[k] ⁣][\![k]\!] for some 3<k<ω3<k<\omega. Neither statement is proved in the paper.

The paper gives no argument for the implication. The natural route goes through Theorem 5.9 with β=ω\beta=\omega, which gives a graph on ω1\omega_1 vertices of chromatic number ω1\omega_1 with no [ ⁣[ω,ω] ⁣][\![\omega,\omega]\!]; a triangle-free subgraph of it supplied by the assertion has the properties Problem 5.10 asks for. Theorem 5.9 is printed under GCH, while Problem 5.10 assumes only CH; the paper does not say that CH suffices for Theorem 5.9 at β=ω\beta=\omega.

Read depth. Claims checked: Problem 5.10, the assertion and the authors' remark were read clause by clause on the page image.

Bears on

  • Problem 740: a subgraph with no odd cycle of length at most 33 is a triangle-free subgraph, so the assertion at α\alpha is the case r=3r=3, m=α\mathfrak m=\alpha of Problem 740's question, restricted to graphs with exactly α\alpha vertices (in such a graph a subgraph of chromatic number α\alpha automatically has α\alpha vertices). Problem 740's page records the later results on graphs with ℵ1\aleph_1 vertices and chromatic number ℵ1\aleph_1.