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Statement
Notation as on the definitions page. A tree here is a graph without circuits (p. 373).
Theorem 9 (p. 373, quoted). "Let . The graph has an edge-decomposition onto the union of trees if and only if ."
So, for infinite , is a union of trees exactly when its vertices can be well-ordered so that each vertex has at most neighbours before it. The paper recalls (p. 373) that Nash-Williams gave the corresponding condition for finite : every finite subgraph on vertices has at most edges.
Lemma 8 (p. 374). If has an edge-decomposition , , of type with for every , then .
Source. P. Erdős and A. Hajnal, On decomposition of graphs, Acta Math. Acad. Sci. Hungar. 18 (1967), 359--377, doi:10.1007/BF02280296; the edition read is named on the source card.
Read depth. Claims checked: Definition 6.1, Theorem 9, Lemma 8 and their proofs (pp. 373--374) were read clause by clause on the page images. The proof of Lemma 8 cites Theorem 6.3 of the authors' 1966 paper, which was not read. Nothing here is independently reviewed.
Proof pointer
P. 374. If , fix a well-ordering in which every vertex has at most earlier neighbours and send the edges from a vertex back to its earlier neighbours into distinct members; no member then has a circuit, since in a circuit the latest vertex would have two edges back in one member. Conversely a tree has colouring number , and Lemma 8 combines the members. Lemma 8 is proved through the set mapping of all neighbours that precede in some member's well-ordering, which has order at most , and Theorem 6.3 of the authors' earlier paper.
Dependencies
Lemma 8 of the same paper; Theorem 6.3 of Erdős and Hajnal, On chromatic number of graphs and set-systems, Acta Math. Acad. Sci. Hungar. 17 (1966), 61--99 (the paper's reference [1]).
Bears on
- Problem 596: through Theorem 10, whose proof applies this theorem with .