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Statement

Let NN be sufficiently large and 3≤y<z≤log⁡N3\le y<z\le\log N. If XX is the set of positive integers divisible by no prime in [y,z][y,z], then

∣X∩[N,2N)∣≪Nlog⁡ylog⁡z.|X\cap[N,2N)|\ll N\frac{\log y}{\log z}.

Source. Bloom, arXiv:2112.03726v2, Lemma 1, printed/PDF p. 6.

Rewritten proof

Let PP be the product of the primes in [y,z][y,z]. Inclusion-exclusion over its squarefree divisors gives

∣X∩[N,2N)∣=∑d∣Pμ(d)(Nd+O(1))=N∏y≤p≤z(1−1p)+O(2π(z)).\begin{aligned} |X\cap[N,2N)| &=\sum_{d\mid P}\mu(d)\left(\frac Nd+O(1)\right)\\ &=N\prod_{y\le p\le z}\left(1-\frac1p\right)+O(2^{\pi(z)}). \end{aligned}

Endpoint rounding changes each count by at most an absolute constant. The Mertens product estimate gives a main term ≪Nlog⁡y/log⁡z\ll N\log y/\log z. Also 2π(z)≤2z≤Nlog⁡22^{\pi(z)}\le2^z\le N^{\log2}, which is o(N/log⁡log⁡N)o(N/\log\log N); since log⁡y/log⁡z≫1/log⁡log⁡N\log y/\log z\gg1/\log\log N, the error is absorbed. This proves the bound.

The same inclusion-exclusion calculation on [1,T][1,T] gives the bound ≪Tlog⁡y/log⁡z\ll T\log y/\log z whenever z≤log⁡Tz\le\log T. This variant is used in Lemma 2.

Dependencies

The external Mertens estimate ∏p≤x(1−1/p)−1≍log⁡x\prod_{p\le x}(1-1/p)^{-1}\asymp\log x is equation (2) on p. 3; Bloom cites Montgomery and Vaughan, Multiplicative Number Theory I, Chapter 2. Bloom also cites their Theorem 3.1 for inclusion-exclusion.

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