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For every fixed sufficiently small and all sufficiently large , at least integers in are -powersmooth.
In particular, for fixed sufficiently small and , at least integers in are -powersmooth for sufficiently large .
Source: published PDF, Lemma 5, p. 9. The first-minimal-power grouping makes the printed exception estimate explicit; this step is valid in the source. The second deduction uses , rather than silently discarding the factor in .
Bears on. Problem 297.
Proof
Put . The near-one Dickman estimate gives -smooth integers. For , . There are consequently at least such integers for large .
If one is not -powersmooth, some prime has a power dividing it that exceeds . For each such , choose the least exponent with . All exceptional integers associated with are divisible by this single minimal power, including those having higher powers. Their number is at most . The union bound over the primes gives at most
exceptions, by the prime number theorem. For large this is at most . Subtracting proves the first assertion.
For the second, once . An integer that is -powersmooth is therefore -powersmooth. Apply the first assertion with .