Research notes on every problem, and a library of the papers behind them. Built from the open erdos repository.
Updated
Statement
Let be the set of integers that cannot be the largest denominator in any Egyptian fraction representation with (p. 3), and let .
Theorem 4 (p. 3). "Let be a positive rational number. The set has zero density, and in fact, if is a real number then
"
The specialization to Problem 292: with the set of for which has a solution , an integer lies in exactly when (a representation of with largest denominator cannot use the denominator ), and by the one-term representation. So equals , , and has density . The lower bound holds because tiny multiples of prime powers lie in ; the upper bound reflects the paper's finding that "all elements of are of this form (the only ambiguity being the exact meaning of 'tiny')" (p. 4), which is the site's "essentially complete description of ".
After the proof (p. 25) the paper records that the argument gives the explicit constants
says that with much more care could be improved to but no further at present. It speculates, without proof, that for fixed and only finitely many , written as with , have , and notes that this would give .
Source. G. Martin, Denser Egyptian fractions, arXiv:math/9811112v1 (18 November 1998), Theorem 4 on p. 3, read on the page image and in the text layer of that preprint; the proof is Section 7 (pp. 24--25). The journal version, Acta Arith. 95 (2000), no. 3, 231--260 (DOI 10.4064/aa-95-3-231-260), was not compared.
Read depth. Claims checked: the statement, the definition of and the counting function were read clause by clause on the page image of p. 3, the remark on p. 4 in the text layer, and the remark on p. 25 on the page image. The proof (pp. 24--25) was read for structure in the text layer; Lemmas 9, 10 and 18, which it invokes, were not checked.
Proof pointer
Lower bound (pp. 24--25): set with large. By Lemma 9, if is the largest denominator of a representation of then has no prime factor larger than (once is so large that the primes dividing the denominator of are below ); so contains every with , and the number of such is asymptotic to by Lemma 10. Upper bound (p. 25): put and , and let be an integer with and . Then lies in and its denominator satisfies , so Lemma 18 (the restatement of Proposition 5 in Section 6) gives a set with , and represents with largest denominator . Hence for large every element of below lies in , a set of size .
Dependencies
Same-paper Lemma 9 (largest prime factor of a largest denominator), Lemma 10 (count of integers with a large prime factor) and Lemma 18 (Proposition 5, which rests on Propositions 7 and 8 of Sections 4 and 5).
Bears on
- Problem 292: with it shows that has density and that the exceptional set has counting function of exact order .
- Problem 285: context only; the two problems share this source.