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Source. Theorem 3, Section 1, p. 2 of Peter Shiu, The denominators of harmonic numbers (Revised), arXiv:1607.02863v2 (30 July 2024; the paper is dated 29 July 2024); proof in Section 4, p. 4. Preprint, not published in a journal (arXiv listing checked). Notation: Hn=cn/dnH_n=c_n/d_n in lowest terms, Dn=lcm(1,…,n)=dnqnD_n=\mathrm{lcm}(1,\ldots,n)=d_nq_n, and for an odd prime pp, Ep={n:1<n<p, p∣cn}E_p=\{n:1<n<p,\ p\mid c_n\} and Qp={n:p∣qn}Q_p=\{n:p\mid q_n\}.

Statement

Theorem 3 (p. 2). For every odd prime pp, the set QpQ_p has a harmonic density, and

δ(Qp)=1log⁡p∑m∈Eplog⁡(1+1m).\delta(Q_p)=\frac{1}{\log p}\sum_{m\in E_p}\log\Bigl(1+\frac1m\Bigr).

The harmonic density is the one the proof computes (p. 4): δ(Qp)=lim⁡x→∞(log⁡x)−1∑n<x, n∈Qp1/n\delta(Q_p)=\lim_{x\to\infty}(\log x)^{-1}\sum_{n<x,\,n\in Q_p}1/n. Since p−1∈Epp-1\in E_p always (p. 2), δ(Qp)≥log⁡(p/(p−1))/log⁡p>0\delta(Q_p)\ge\log(p/(p-1))/\log p>0. For p=3p=3, E3={2}E_3=\{2\} and δ(Q3)=log⁡(3/2)/log⁡3\delta(Q_3)=\log(3/2)/\log3.

Proof pointer and sketch (Section 4)

By Theorem 2, QpQ_p is the disjoint union of the intervals mpa≤n<(m+1)pamp^a\le n<(m+1)p^a, m∈Epm\in E_p, a≥1a\ge1. Each such interval contributes log⁡(1+1/m)+O(1/(mpa))\log(1+1/m)+O(1/(mp^a)) to the harmonic sum, so summing over a<ba<b gives b∑m∈Eplog⁡(1+1/m)+O(log⁡p)b\sum_{m\in E_p}\log(1+1/m)+O(\log p), and the tail between xx and the next power of pp contributes O(log⁡p)O(\log p); dividing by log⁡x\log x gives the limit. The argument is half a page, read through here and not independently reviewed.

The same section counts QpQ_p along powers of pp (display (3), p. 4): for x=pbx=p^b, the intervals with a≤b−1a\le b-1 give Qp(x)=∣Ep∣(pb−p)/(p−1)Q_p(x)=|E_p|(p^b-p)/(p-1). The print then writes Qp(x)∼∣Ep∣x/pQ_p(x)\sim|E_p|x/p as x=pb→∞x=p^b\to\infty; the exact count it displays is asymptotic to ∣Ep∣x/(p−1)|E_p|x/(p-1) instead. Recomputed here for p=3p=3, x=38x=3^8: Q3(x)=3279=(38−3)/2Q_3(x)=3279=(3^8-3)/2, against x/3=2187x/3=2187. The discrepancy is in the asymptotic only and does not touch Theorem 3. The paper also remarks (p. 4) that, because QpQ_p consists of long runs of consecutive integers, it has no asymptotic density.

Dependencies and read depth

Theorem 2 and the elementary estimate ∑x≤n<y1/n=log⁡(y/x)+O(1/x)\sum_{x\le n<y}1/n=\log(y/x)+O(1/x). Read depth: claims checked; the proof read through, not verified.

Relation to Problem 291

In the notation of Problem 291, qn=(an,Ln)q_n=(a_n,L_n), so QpQ_p is the set of nn with p∣(an,Ln)p\mid(a_n,L_n). The theorem measures, prime by prime, how much of the integers the second question's answer covers; it is unconditional but says nothing about how the sets QpQ_p for different pp overlap. The paper's Conjecture for the first question rests on display (3) of this proof (Section 7, p. 6), not on the theorem itself.

Bears on. #291 (the harmonic density of each set {n:p∣(an,Ln)}\{n:p\mid(a_n,L_n)\}, pp an odd prime; nothing on the first question).